Elements of Geometry: Containing the First Six Books of Euclid, with a Supplement on the Quadrature of the Circle, and the Geometry of Solids: to which are Added Elements of Plane and Spherical TrigonometryCollins & Hannay, 1860 - 333 sider |
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Resultat 1-3 av 35
Side 98
... ABCD is rectangular , and it has been shewn to be equi lateral ; therefore it is a square ; and it is inscribed in the circle ABCD . Which was to be done . PROP . VII . PROB . To describe a square about a given circle . Let ABCD be the ...
... ABCD is rectangular , and it has been shewn to be equi lateral ; therefore it is a square ; and it is inscribed in the circle ABCD . Which was to be done . PROP . VII . PROB . To describe a square about a given circle . Let ABCD be the ...
Side 211
... ABCD , because ABCD is greater than the sum of the in- scribed prisms . Much more , therefore , Much more , therefore , is the excess of the circum- scribed prisms above the pyramid , less than the solid Z. A series of prisms of the ...
... ABCD , because ABCD is greater than the sum of the in- scribed prisms . Much more , therefore , Much more , therefore , is the excess of the circum- scribed prisms above the pyramid , less than the solid Z. A series of prisms of the ...
Side 214
... ABCD be a cylinder , and EF a parallelopiped having equal bases , viz . the circle AGB and the parallelogram EH , and having also equal altitudes ; the cylinder ABCD is equal to the parallelopiped EF .. M B K PRN QS H If not , let them ...
... ABCD be a cylinder , and EF a parallelopiped having equal bases , viz . the circle AGB and the parallelogram EH , and having also equal altitudes ; the cylinder ABCD is equal to the parallelopiped EF .. M B K PRN QS H If not , let them ...
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Vanlige uttrykk og setninger
ABC is equal ABCD altitude angle ABC angle ACB angle BAC angle EDF arch AC base BC bisected centre circle ABC circumference cosine cylinder demonstrated diameter draw equal and similar equal angles equiangular equilateral equilateral polygon equimultiples Euclid exterior angle fore four right angles given straight line greater hypotenuse inscribed join less Let ABC Let the straight line BC magnitudes meet multiple opposite angle parallel parallelogram perpendicular polygon prism PROB produced proportionals proposition Q. E. D. COR Q. E. D. PROP radius ratio rectangle contained rectilineal figure remaining angle segment semicircle side BC sine solid angle solid parallelopipeds spherical angle spherical triangle straight line AC THEOR third touches the circle triangle ABC triangle DEF wherefore