Elements of Geometry: Containing the First Six Books of Euclid, with a Supplement on the Quadrature of the Circle, and the Geometry of Solids: to which are Added Elements of Plane and Spherical TrigonometryCollins & Hannay, 1860 - 333 sider |
Inni boken
Resultat 1-3 av 88
Side 125
... base BC ; and DK , KL , any number of them , each equal to the base CD ; and join AG , AH , AK , AL . Then , because CB , BG , GH are all equal , the triangles AHG , AGB , ABC are all equal ( 38. 1. ) ; Therefore , whatever multiple the ...
... base BC ; and DK , KL , any number of them , each equal to the base CD ; and join AG , AH , AK , AL . Then , because CB , BG , GH are all equal , the triangles AHG , AGB , ABC are all equal ( 38. 1. ) ; Therefore , whatever multiple the ...
Side 199
... base LF is of the base AF , the same multiple is the solid LV of the solid AV ; for the same reason , what- ever multiple the base NF is of the base HF , the same multiple is the solid NV of the solid ED : And if the base LF be equal to the ...
... base LF is of the base AF , the same multiple is the solid LV of the solid AV ; for the same reason , what- ever multiple the base NF is of the base HF , the same multiple is the solid NV of the solid ED : And if the base LF be equal to the ...
Side 203
... base AE to the base LQ , so the base CD to the base LQ , as has been proved : therefore as the solid AE to the solid LR , so is the solid CF to the solid LR ; and therefore the solid AE is equal ( 9. 5. ) to the solid CF. But let the ...
... base AE to the base LQ , so the base CD to the base LQ , as has been proved : therefore as the solid AE to the solid LR , so is the solid CF to the solid LR ; and therefore the solid AE is equal ( 9. 5. ) to the solid CF. But let the ...
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Vanlige uttrykk og setninger
ABC is equal ABCD altitude angle ABC angle ACB angle BAC angle EDF arch AC base BC bisected centre circle ABC circumference cosine cylinder demonstrated diameter draw equal and similar equal angles equiangular equilateral equilateral polygon equimultiples Euclid exterior angle fore four right angles given straight line greater hypotenuse inscribed join less Let ABC Let the straight line BC magnitudes meet multiple opposite angle parallel parallelogram perpendicular polygon prism PROB produced proportionals proposition Q. E. D. COR Q. E. D. PROP radius ratio rectangle contained rectilineal figure remaining angle segment semicircle side BC sine solid angle solid parallelopipeds spherical angle spherical triangle straight line AC THEOR third touches the circle triangle ABC triangle DEF wherefore