Elements of Geometry: Containing the First Six Books of Euclid, with a Supplement on the Quadrature of the Circle, and the Geometry of Solids: to which are Added Elements of Plane and Spherical TrigonometryCollins & Hannay, 1860 - 333 sider |
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Resultat 1-3 av 12
Side 240
... cosine of the arch BD , and CG the cosine of the half of BD ; whence the cosine of the half of any arch BD , of a circle of which the radius = 1 , is a mean propor- tional between and 1 + cos BD . Or , for the greater generality ...
... cosine of the arch BD , and CG the cosine of the half of BD ; whence the cosine of the half of any arch BD , of a circle of which the radius = 1 , is a mean propor- tional between and 1 + cos BD . Or , for the greater generality ...
Side 241
... cosine of the common difference BC as the sine of AC , the middle arch , to half the sum of the sines of AB and AD , the extreme arches . Draw CE to the centre : lot BF , CG , and DH perpendic : 1r to AE , be the sines of the arches AB ...
... cosine of the common difference BC as the sine of AC , the middle arch , to half the sum of the sines of AB and AD , the extreme arches . Draw CE to the centre : lot BF , CG , and DH perpendic : 1r to AE , be the sines of the arches AB ...
Side 269
... cosine of half the sum of these sides , is to the cosine of half their difference , as the cotangent of half the angle contained between them , to the tangent of half the sum of the angles opposite to them . COR . 2. If therefore A , B ...
... cosine of half the sum of these sides , is to the cosine of half their difference , as the cotangent of half the angle contained between them , to the tangent of half the sum of the angles opposite to them . COR . 2. If therefore A , B ...
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Vanlige uttrykk og setninger
ABC is equal ABCD altitude angle ABC angle ACB angle BAC angle EDF arch AC base BC bisected centre circle ABC circumference cosine cylinder demonstrated diameter draw equal and similar equal angles equiangular equilateral equilateral polygon equimultiples Euclid exterior angle fore four right angles given straight line greater hypotenuse inscribed join less Let ABC Let the straight line BC magnitudes meet multiple opposite angle parallel parallelogram perpendicular polygon prism PROB produced proportionals proposition Q. E. D. COR Q. E. D. PROP radius ratio rectangle contained rectilineal figure remaining angle segment semicircle side BC sine solid angle solid parallelopipeds spherical angle spherical triangle straight line AC THEOR third touches the circle triangle ABC triangle DEF wherefore