Ray's Algebra, Part First: On the Analytic and Inductive Methods of Instruction, with Numerous Practical Exercises, Designed for Common Schools and Academies

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Sargent, Wilson & Hinkle, 1848 - 240 sider

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Side 100 - Multiply the numerators together for a new numerator, and the denominators together for a new denominator.
Side 22 - Required the distance from A to B, from B to C, and from C to D.
Side 176 - Multiply the divisor, thus increased, by the last figure of the root; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend.
Side 136 - In any proportion, the product of the means is equal to the product of the extremes.
Side 122 - A hare is 50 leaps before a greyhound, and takes 4 leaps to the greyhound's 3 ; but 2 of the greyhound's leaps are equal to 3 of the hare's ; how many leaps must the greyhound take to catch the hare ? Let x be the number of leaps taken by the hound.
Side 62 - The square of the sum of two quantities is equal to the square of the first, plus twice the product of the first by the second, plus the square of the second.
Side 78 - To find the greatest common divisor of three or more quantities, first find the greatest common divisor of two of them ; then, of that divisor and one of the other quantities, and so on. The last divisor thus found, will be the greatest common divisor sought.
Side 59 - Divide the first term of the dividend by the first term of the divisor, and write the result as the first term of the quotient.
Side 137 - A farmer has 2 horses, and a saddle worth 25 dollars ; now, if the saddle be put on the first horse, his value will be double that of the second ; but, if the saddle be put on the second horse, his value will be three times that of the first.
Side 219 - The fore wheel of a carriage makes 6 revolutions more than the hind wheel in going 120 yards; but if the periphery of each wheel be increased one yard, it will make only 4 revolutions more than the hind wheel in the same space.

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