Orr's Circle of the Sciences: Organic nature, vols. 1-3 (1854-1856)William Somerville Orr W.S. Orr and Company, 1854 |
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Side vi
... exercises , all of which we strongly recommend him to perform , and to test his knowledge of the text by writing out from memory ... exercise care and judgment in ascertaining whether he has really understood what he has read . There are ...
... exercises , all of which we strongly recommend him to perform , and to test his knowledge of the text by writing out from memory ... exercise care and judgment in ascertaining whether he has really understood what he has read . There are ...
Side vii
... Exercises . 69 , 85 Propositions , & c . , of Book II . . 87-92 of Book III . 97-112 On Impossible Expressions The Convergent and Divergent Series . The Binomial Theorem 266 , 269 et seq . On the Calculation of Logarithms . . 275 ...
... Exercises . 69 , 85 Propositions , & c . , of Book II . . 87-92 of Book III . 97-112 On Impossible Expressions The Convergent and Divergent Series . The Binomial Theorem 266 , 269 et seq . On the Calculation of Logarithms . . 275 ...
Side 2
... exercises his understanding . To make , in this way , the passage from arithmetic to geometry , an abrupt transition from the mechanical to the intellectual , we conceive to be a capital defect in educational training . Arithmetic is as ...
... exercises his understanding . To make , in this way , the passage from arithmetic to geometry , an abrupt transition from the mechanical to the intellectual , we conceive to be a capital defect in educational training . Arithmetic is as ...
Side 4
... exercise has not been combined with intellectual gratification ; and whether there be not an abstract beauty in the result arrived at , that awakens pleasurable feelings , practically realised , though hard to be described . We think ...
... exercise has not been combined with intellectual gratification ; and whether there be not an abstract beauty in the result arrived at , that awakens pleasurable feelings , practically realised , though hard to be described . We think ...
Side 12
... exercise himself in the process , by showing that the following statements are true : - ( 1. ) 4214 X 24 = 101136 . ( 2. ) 658 X 243 = 159894 . ( 3. ) 3264 X2300 = 7507200 . ( 4. ) 15607 X 309448288058 . 2647 356 356 2647 15882 2492 ...
... exercise himself in the process , by showing that the following statements are true : - ( 1. ) 4214 X 24 = 101136 . ( 2. ) 658 X 243 = 159894 . ( 3. ) 3264 X2300 = 7507200 . ( 4. ) 15607 X 309448288058 . 2647 356 356 2647 15882 2492 ...
Vanlige uttrykk og setninger
ABCD Algebra arithmetic base Binomial Theorem bisect calculation called centre chord circumference coefficient common Completing the square contained cotan decimals denominator describe diameter divided dividend divisor draw ellipse equal angles equation equiangular equilateral Euclid EXAMPLES FOR EXERCISE expression exterior angle factors figure formula fraction frustum geometrical progression geometry given straight line greater h₂ Hence inscribed intersecting join latter less logarithm magnitudes manner measure multiplied operation parallel parallelogram perpendicular plane polygon prism Prop proportion proved Q. E. D. PROPOSITION quantity quotient radius ratio rectangle remainder result right angles rule sides sines solid angle sphere square root subtract suppose theorem third triangle ABC trigonometrical
Populære avsnitt
Side 86 - If two triangles have two sides of the one equal to two sides of the...
Side 60 - If a straight line meets two straight lines, so as to make the two interior angles on the same side of it taken together less than two right angles...
Side 58 - ... equal angles in each ; then shall the other sides be equal each to each : and also the third angle of the one to the third angle of the other.
Side 45 - A circle is a plane figure contained by one line, which is called the circumference, and is such that all straight lines drawn from a certain point within the figure to the circumference, are equal to one another.
Side 190 - Divide the first term of the dividend by the first term of the divisor, and write the result as the first term of the quotient. Multiply the whole divisor by the first term of the quotient, and subtract the product from the dividend.
Side 47 - Let it be granted that a straight line may be drawn from any one point to any other point.
Side 151 - Equal parallelograms which have one angle of the one equal to one angle of the other, have their sides about the equal angles reciprocally proportional ; and parallelograms that have one angle of the one equal to one angle of the other, and their sides about the equal angles reciprocally proportional, are equal to one another.
Side 96 - angle in a segment' is the angle contained by two straight lines drawn from any point in the circumference of the segment, to the extremities of the straight line which is the base of the segment.
Side 46 - A rhombus, is that which has all its sides equal, but its angles are not right angles.
Side 66 - From this it is manifest how to a given straight line to apply a parallelogram, which shall have an angle equal to a given rectilineal angle, and shall be equal to a given rectilineal figure, viz.