 | Robert Simson - 1806 - 546 sider
...angle of a right angled triangle to the base, is a mean proportional between the segments of the base : and also that each of the sides is a mean proportional between the base, and its segment adjacent to that side: because in the triangles BDA, ADC, BD is to DA, as DA... | |
 | Euclid - 1810 - 554 sider
...to ABC, are equiangular and similar to each other. Therefore, in a right angled, &c. QED . Con. From this it is manifest, that the perpendicular drawn from the right angle of a right angled triangle to the base, is a mean proportional between the segments of the base : and also... | |
 | Euclides - 1816 - 588 sider
...to ABC, are equiangular and similar to each other. Therefore, in a right angled, &c. QED COR. From this it is manifest that the perpendicular drawn from the right angle of a right angled triangle to the base, is a mean proportional between the segments of the .s. base: And... | |
 | John Playfair - 1819 - 350 sider
...ABC, are equiangular and similar to one another- Therefore, in a right angled, Jkc Q, ED COR. From this it is manifest, that the perpendicular drawn, from the right angle of a right angled-triangle, to the base, is a mean proportional between the segments of the base ; and also... | |
 | Peter Nicholson - 1825 - 1046 sider
...ABC, are equiangular and similar to each other. Therefore in a right analed, &c. QED COR. From thii it is manifest, that the perpendicular drawn from the right angle of a right angled triangle to the base, is a mean proportional between the segment«- of the base : And... | |
 | Euclides - 1826 - 226 sider
...drawn from the right angle at the base, it is a mean proportional between the segments of the base; and also that each of the sides is a mean proportional between the base and its segment adjacent to that side. Deduction. PROPOSITION IX. PROBLEM. From a given right... | |
 | Euclid - 1826 - 234 sider
...drawn from the right angle at the base, it is a mean proportional between the segments of the base ; and also that each of the sides is a mean proportional between the base and its segment adjacent to that side. Deduction. To divide a given finite right line into two... | |
 | Robert Simson - 1827 - 546 sider
...to ABC, are equiangular and similar to each other. Therefore, in a right angled, &c. QED COR. From this it is manifest that the perpendicular drawn from the right angle of a right angled triangle to the base, is a mean proportional between the segments of the base, and also... | |
 | Euclides - 1833 - 304 sider
...contained by those chords, will be a right £_ (Prop. 31, 3) ; and the perpendicular, from this right f_ on the hypotenuse, is a mean proportional between the segments of the hypotenuse (Cor. 8, 6.). Cor. 1. In like manner mean proportionals can be found between the given lines and this... | |
 | Euclid - 1835 - 540 sider
...ABC, are equiangular and similar to each other. Therefore, " in a right angled," &c. QED COR. From this it is manifest, that the perpendicular drawn from the right angle of a right angled triangle to tlie base, is a mean proportional between the segments of the base : And also,... | |
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From this it is manifest, that the perpendicular drawn from the right angle of a right-angled triangle to the base, is a mean proportional between the segments of the base; and also that each of the sides is a mean proportional between the base, and... 
