The school edition. Euclid's Elements of geometry, the first six books, by R. Potts. corrected and enlarged. corrected and improved [including portions of book 11,12].1864 |
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Side 2
... straight lines that contain the angle meet one another , is put between the other two letters , and one of these two is somewhere upon one of these straight lines , and the other upon the other line . Thus the angle which is contained ...
... straight lines that contain the angle meet one another , is put between the other two letters , and one of these two is somewhere upon one of these straight lines , and the other upon the other line . Thus the angle which is contained ...
Side 7
... straight line . Let AB be the given straight line . It is required to describe an equilateral triangle upon AB . C D B E From the center A , at the distance AB , describe the circle BCD ; ( post . 3. ) from the center B , at the ...
... straight line . Let AB be the given straight line . It is required to describe an equilateral triangle upon AB . C D B E From the center A , at the distance AB , describe the circle BCD ; ( post . 3. ) from the center B , at the ...
Side 8
... straight line AL is equal to BC . ( ax . 1. ) Wherefore from the given point A , a straight line AL has been drawn equal to the given straight line BC . Which was to be done . PROPOSITION III . PROBLEM . From the greater of two given ...
... straight line AL is equal to BC . ( ax . 1. ) Wherefore from the given point A , a straight line AL has been drawn equal to the given straight line BC . Which was to be done . PROPOSITION III . PROBLEM . From the greater of two given ...
Side 13
... straight line AF shall bisect the angle BAC . Because AD is equal to AE , ( constr . ) and AF is common to the two ... straight line AF . Q.E.F. PROPOSITION X. PROBLEM . To bisect a given finite straight line , that is , to divide it ...
... straight line AF shall bisect the angle BAC . Because AD is equal to AE , ( constr . ) and AF is common to the two ... straight line AF . Q.E.F. PROPOSITION X. PROBLEM . To bisect a given finite straight line , that is , to divide it ...
Side 14
Euclides Robert Potts. PROPOSITION XI . PROBLEM . To draw a straight line at right angles to a given straight line , from a given point in the same . Let AB be the given straight line , and Ca given point in it . It is required to draw a ...
Euclides Robert Potts. PROPOSITION XI . PROBLEM . To draw a straight line at right angles to a given straight line , from a given point in the same . Let AB be the given straight line , and Ca given point in it . It is required to draw a ...
Andre utgaver - Vis alle
The School Edition. Euclid's Elements of Geometry, the First Six Books, by R ... Euclides Ingen forhåndsvisning tilgjengelig - 2023 |
The School Edition. Euclid's Elements of Geometry, the First Six Books, by R ... Euclides Ingen forhåndsvisning tilgjengelig - 2018 |
The School Edition. Euclid's Elements of Geometry, the First Six Books, by R ... Euclides Ingen forhåndsvisning tilgjengelig - 2016 |
Vanlige uttrykk og setninger
A₁ ABCD AC is equal Algebraically angle ABC angle ACB angle BAC angle equal Apply Euc base BC chord circle ABC constr describe a circle diagonals diameter divided double draw equal angles equiangular equilateral triangle equimultiples Euclid Euclid's Elements exterior angle Geometrical given angle given circle given line given point given straight line gnomon greater hypotenuse inscribed intersection isosceles triangle less Let ABC line BC lines be drawn multiple opposite angles parallelogram parallelopiped pentagon perpendicular polygon problem produced Prop proportionals proved Q.E.D. PROPOSITION radius ratio rectangle contained rectilineal figure remaining angle right angles right-angled triangle segment semicircle shew shewn similar solid angle square on AC tangent THEOREM touch the circle trapezium triangle ABC twice the rectangle vertex vertical angle wherefore
Populære avsnitt
Side 112 - Guido, with a burnt stick in his hand, demonstrating on the smooth paving-stones of the path, that the square on the hypotenuse of a right-angled triangle is equal to the sum of the squares on the other two sides.
Side 83 - If a straight line be bisected, and produced to any point ; the rectangle contained by the whole line thus produced, and the part of it produced, together with the square...
Side 48 - If two triangles have two sides of the one equal to two sides of the other, each to each ; and...
Side 238 - The first of four magnitudes is said to have the same ratio to the second, which the third has to the fourth, when any equimultiples whatsoever of the first and third being taken, and any equimultiples whatsoever of the second and fourth; if the multiple of the first be less than that of the second, the multiple of the third is also less than that of the fourth...
Side 198 - A LESS magnitude is said to be a part of a greater magnitude, when the less measures the greater, that is, ' when the less is contained a certain number of times exactly in the greater.
Side 271 - SIMILAR triangles are to one another in the duplicate ratio of their homologous sides.
Side 81 - If a straight line be divided into any two parts, the rectangle contained by the whole and one of the parts, is equal to the rectangle contained by the two parts, together with the square of the aforesaid part.
Side 115 - angle in a segment' is the angle contained by two straight lines drawn from any point in the circumference of the segment, to the extremities of the straight line which is the base of the segment.
Side 341 - On the same base, and on the same side of it, there cannot be two triangles...
Side 24 - ... twice as many right angles as the figure has sides ; therefore all the angles of the figure together with four right angles, are equal to twice as many right angles as the figure has sides.