Elements of Plane and Spherical Trigonometry: With Practical ApplicationsR. S. Davis, 1861 - 490 sider |
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Resultat 1-5 av 66
Side 41
... consequently A D is parallel to BC ( Prop . XX . ) ; therefore the figure ABCD is a parallelogram . PROPOSITION XXXIV . THEOREM . - 113. The diagonals of every parallelogram bisect each other . Let ABCD be a parallelogram , and A C , DB ...
... consequently A D is parallel to BC ( Prop . XX . ) ; therefore the figure ABCD is a parallelogram . PROPOSITION XXXIV . THEOREM . - 113. The diagonals of every parallelogram bisect each other . Let ABCD be a parallelogram , and A C , DB ...
Side 40
... consequently AD is parallel to BC ( Prop . XX . ) ; therefore the figure ABCD is a parallelogram . PROPOSITION XXXIV . - THEOREM . 113. The diagonals of every parallelogram bisect each other . Let ABCD be a parallelogram , D C and A C ...
... consequently AD is parallel to BC ( Prop . XX . ) ; therefore the figure ABCD is a parallelogram . PROPOSITION XXXIV . - THEOREM . 113. The diagonals of every parallelogram bisect each other . Let ABCD be a parallelogram , D C and A C ...
Side 78
... consequently equal ( Prop . XVIII . Bk . I. ) . If from the quadrilateral A B E D , we take away the tri- angle A D F , there will remain the parallelogram ABEF ; and if from the same quadrilateral A B E D , we take away the triangle ...
... consequently equal ( Prop . XVIII . Bk . I. ) . If from the quadrilateral A B E D , we take away the tri- angle A D F , there will remain the parallelogram ABEF ; and if from the same quadrilateral A B E D , we take away the triangle ...
Side 88
... consequently the tri- angle and the square have the same altitude AB ( Prop . L K 4 I B D C F E G XXV . Bk . I. ) ; and they also have the same base BH ; hence the triangle is equivalent to half the square ( Prop . II . ) . The triangle ...
... consequently the tri- angle and the square have the same altitude AB ( Prop . L K 4 I B D C F E G XXV . Bk . I. ) ; and they also have the same base BH ; hence the triangle is equivalent to half the square ( Prop . II . ) . The triangle ...
Side 90
... consequently , since the triangles HBN , A B C are both right - angled , and have also the sides BH , BA equal , their hypothenuses BN , B C are equal ( Prop . VI . Cor . , Bk . I. ) . But BC is equal to BF ; therefore BN is equal to BF ...
... consequently , since the triangles HBN , A B C are both right - angled , and have also the sides BH , BA equal , their hypothenuses BN , B C are equal ( Prop . VI . Cor . , Bk . I. ) . But BC is equal to BF ; therefore BN is equal to BF ...
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Elements of Plane and Spherical Trigonometry: With Practical Applications Benjamin Greenleaf Uten tilgangsbegrensning - 1876 |
Elements of Plane and Spherical Trigonometry: With Practical Applications Benjamin Greenleaf Uten tilgangsbegrensning - 1862 |
Elements of Plane and Spherical Trigonometry: With Practical Applications Benjamin Greenleaf Uten tilgangsbegrensning - 1867 |
Vanlige uttrykk og setninger
A B C ABCD adjacent angles altitude angles ACD angles equal base bisect centre chord circle circumference cone convex surface cosec cosine Cotang diagonal diameter distance divided drawn equal angles equal Prop equiangular equilateral equivalent exterior angle feet four right angles frustum gles greater half the sum homologous homologous sides hypothenuse inches included angle inscribed less Let ABC line A B logarithm mean proportional multiplied parallelogram parallelopipedon perimeter perpendicular polyedron prism PROPOSITION pyramid quadrilateral radii radius ratio rectangle regular polygon right angles Prop right-angled triangle Scholium secant secant line segment side A B side BC similar slant height solidity solve the triangle sphere spherical triangle Tang tangent THEOREM triangle ABC trigonometric functions vertex
Populære avsnitt
Side 17 - All the interior angles of any rectilineal figure, together with four right angles, are equal to twice as many right angles as the figure has sides.
Side 57 - If two triangles have two angles of the one equal to two angles of the other, each to each, and also one side of the one equal to the corresponding side of the other, the triangles are congruent.
Side 155 - The convex surface of the cylinder is equal to the circumference of its base multiplied by its altitude (Prop.
Side 28 - If any number of quantities are proportional, any antecedent is to its consequent as the sum of all the antecedents is to the sum of all the consequents. Let a : b = c : d = e :f Now ab = ab (1) and by Theorem I.
Side 118 - The radius of a sphere is a straight line, drawn from the centre to any point of the...
Side 98 - If a straight line is perpendicular to each of two straight lines at their point of intersection, it is perpendicular to the plane of those lines.
Side 144 - The convex surface of this prism is equal to the perimeter of its base multiplied by its altitude, AG (Prop.
Side 176 - Find the area of the sector having' the same arc with the segment, and also the area of the triangle formed by the chord of the segment and the radii of the sector. Then...
Side 14 - Straight lines which are parallel to the same line are parallel to each other. Let the straight lines AB, CD be each parallel to the line EF ; then are they parallel to each other.
Side 95 - STRAIGHT line is perpendicular to a plane, when it is perpendicular to every straight line which it meets in that plane.