Elements of Geometry, and Plane and Spherical Trigonometry: With Numerous Practical ProblemsIvison, Blakeman, Taylor, 1860 - 453 sider |
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Side 14
... Equivalent Magnitudes are those which , though they do not admit of coincidence when applied the one to the other , still have common measures , and are therefore numerically equal . 47. Similar Figures have equal angles , and the same ...
... Equivalent Magnitudes are those which , though they do not admit of coincidence when applied the one to the other , still have common measures , and are therefore numerically equal . 47. Similar Figures have equal angles , and the same ...
Side 41
... equivalent , or equal in respect to area or sur- face . Let ABEC and ABDF be two C parallelograms on the same base AB , and between the sam paral- lels AB and CD ; we are to prove that these two parallelograms are equal . = E F A Now ...
... equivalent , or equal in respect to area or sur- face . Let ABEC and ABDF be two C parallelograms on the same base AB , and between the sam paral- lels AB and CD ; we are to prove that these two parallelograms are equal . = E F A Now ...
Side 42
... equivalent . Let the two A's ABE and ABF have the same base AB , and be be- tween the same parallels AB and EF ; then we are to prove that they are equal in surface .. E F A B From B draw the line BD , par- allel to AF ; and from A draw ...
... equivalent . Let the two A's ABE and ABF have the same base AB , and be be- tween the same parallels AB and EF ; then we are to prove that they are equal in surface .. E F A B From B draw the line BD , par- allel to AF ; and from A draw ...
Side 43
... equivalent parallelogram FH ; therefore , the △ ABD = the △ EFG , ( Ax . 7 ) . THEOREM XXX . If a triangle and a parallelogram are upon the same or equal bases , and between the same parallels , the triangle is equiva- lent to one ...
... equivalent parallelogram FH ; therefore , the △ ABD = the △ EFG , ( Ax . 7 ) . THEOREM XXX . If a triangle and a parallelogram are upon the same or equal bases , and between the same parallels , the triangle is equiva- lent to one ...
Side 45
... equivalent to one half this rectangle , ( Th . 30 ) . Therefore , the area of the A is measured by AB × AD , or one half the product of its base by its altitude . Hence the theorem ; the area of any plane triangle , etc. THEOREM XXXIV ...
... equivalent to one half this rectangle , ( Th . 30 ) . Therefore , the area of the A is measured by AB × AD , or one half the product of its base by its altitude . Hence the theorem ; the area of any plane triangle , etc. THEOREM XXXIV ...
Andre utgaver - Vis alle
Elements of Geometry and Plane and Spherical Trigonometry: With Numerous ... Horatio Nelson Robinson Uten tilgangsbegrensning - 1867 |
Elements of Geometry, and Plane and Spherical Trigonometry: With Numerous ... Horatio Nelson Robinson Uten tilgangsbegrensning - 1865 |
Elements of Geometry, and Plane and Spherical Trigonometry: With Numerous ... Horatio Nelson Robinson Uten tilgangsbegrensning - 1860 |
Vanlige uttrykk og setninger
AB² ABCD altitude angle opposite axis bisected chord circle circumference circumscribed common cone convex surface cos.a cos.b cos.c Cosine Cotang diagonal diameter dicular difference distance divided draw equal angles equation equiangular equivalent find the angle four magnitudes frustum given line greater half Hence the theorem homologous hypotenuse included angle inscribed intersect isosceles less Let ABC logarithm measured multiplied N.sine number of sides opposite angles parallelogram parallelopipedon pendicular perpen perpendicular plane ST polyedron PROBLEM produced Prop proportion PROPOSITION prove pyramid quadrantal radii radius rectangle regular polygon right angles right-angled spherical triangle right-angled triangle SCHOLIUM secant segment similar sin.a sin.b sin.c sine solid angles sphere SPHERICAL TRIGONOMETRY straight line subtracting Tang tangent three angles three sides triangle ABC triangular prisms triedral angles TRIGONOMETRY vertex vertical angle volume
Populære avsnitt
Side 320 - If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz.
Side 65 - If four magnitudes are in proportion, the sum of the first and second is to their difference as the sum of the third and fourth is to their difference.
Side 121 - In a given circle to inscribe a triangle equiangular to a given triangle. Let ABC be the given circle, and DEF the given triangle ; it is required to inscribe in the circle ABC a triangle equiangular to the triangle DEF.
Side 56 - If a straight line be divided into two equal parts, and also into two unequal parts; the rectangle contained by the unequal parts, together with the square of the line between the points of section, is equal to the square of half the line.
Side 34 - Conversely: if two angles of a triangle are equal, the sides opposite to them are equal, and the triangle it itosceles.
Side 126 - To inscribe a regular polygon of a certain number of sides in a given circle, we have only to divide the circumference into as many equal parts as the polygon has sides : for the arcs being equal, the chords AB, BC, CD, &c.
Side 22 - If two parallel lines are cut by a third straight line, the sum of the two interior angles on the same side of the secant line is equal to two right angles.
Side 277 - The logarithm of any power of a number is equal to the logarithm of the number multiplied by the exponent of the power.
Side 94 - The angle in a semicircle is a right angle ; the angle in a segment greater than a semicircle is less than a right angle ; and the angle in a segment less than a semicircle is greater than a right angle.
Side 30 - Therefore all the interior angles of the figure, together with four right angles, are equal to twice as many right angles as the figure has sides.