 | John Ward (of Chester.) - 1724 - 480 sider
...a Spheroid, whofe Content may be computed, by Theorem 22. Page 427. which gives thefe two Rules. , To Twice the Square of the Bung Diameter Add the \Square of the Head Diameter j multiply that Sum into 'the Length, and divide the Product by 1077,15. ) Viz. 3,8197 X 282 for Ale... | |
 | John Ward (of Chester.) - 1728 - 476 sider
...ofaparabolick Spindle, and its Content is computed, as by Theorem 27. Page 432. Which gives this Rule. fTo Twice the Square of the Bung Diameter, add the \ Square of the Head Diameter ; from their Difference 1f?f rTo 'J SuhftraSfour Tenths of the Square of the Difference millf, "I Oy... | |
 | John Ward (of Chester.) - 1747 - 516 sider
...parabolick Spindle, and its Content is computed, as by Theorem 27. Page 432. Which gives this Rule. To twice the Square of the Bung Diameter, add the Square of the Head Diameter; from their Difference m . J fubtraft four Tenths of the Square of the Difference Aulle < Of jj^ j)¡ameters... | |
 | John Ward - 1747 - 492 sider
...at the Bulpe, and the Content may be found fay 'Theorem 25. Page 430. Which gives thefe Rules. fTo the Square of the Bung Diameter add the Square | of the Head Diameter ; multiply their Sum into the little !• 4 Length, and divide the Produft by 718, 08 (viz. j 2,54^4... | |
 | 1801 - 658 sider
...-J O4'/ .-724 wine gallons. PROBLEM 111. 5Fi find the content of a cask of the third farm, RULE. To the square of the bung diameter add the square of the head diameter j multiply the sum bjr the length, and the product by '0014, for ale gallons, or by -0017, for wine... | |
 | Peter Jonas - 1804 - 148 sider
...property as the middle frustum of every parabolic spindle, must be gauged by the following general Rule. To twice the square of the bung- diameter, add the square of the head diameter, and from this sum take -i^ihs (.4) of the square of the difference of the said dia.Tveiers ; multiply the... | |
 | Oliver Welch - 1857 - 244 sider
...heads, &c. CASE II. 7 o gunge a cask representing the middle frustum of an elliptic spindle. RULE. 1 — To twice the square of the bung diameter, add the...bung diameter, square the difference, and subtract J of the square of the difference from the reserved sum ; multiply the remainder by the length of the... | |
 | John Dougall - 1815 - 514 sider
...casks may be found in a ditfi'ieiit way, in the following manner. For the spheroid or lti variety. To twice the square of the bung diameter add the square of \\n- head diameter; multiply this sum by the length of the cask, and dhide the product by 1077 . 15... | |
 | Peter Nicholson - 1825 - 1046 sider
...12'018 gallons, 1 14724 wine gallons. Prob. 1 4. To find the content of a cask of the third form. To the square of the bung diameter, add the square of the head diameter ; multiply the sum by the lengtk, and the product again by the length, and the product again by '0014... | |
 | Oliver Welch - 1826 - 242 sider
...CASE IL. Tf' guage a cask representing the middle frustum• of ftn ' ' ''" "' ROLE 1. — Tortwice the square of the bung diameter, add the square of....bung diameter, square the difference, and subtract $• of the square of the difference from the reserved sum ; multiply the remainder by the length of... | |
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RULE. — To the square of the bung diameter add the square of the head diameter ; multiply the sum by the length, and the product by .0014 for ale gallons, or by .0017 for wine gallons. 
