Vectors and Rotors: With ApplicationsE. Arnold, 1903 - 204 sider |
Inni boken
Resultat 1-5 av 23
Side 19
... dividing a vector by a number means dividing its length by that number . n These definitions , although first obtained for whole numbers n , retain a meaning when n is any number , positive or negative , whole or fractional or incommen ...
... dividing a vector by a number means dividing its length by that number . n These definitions , although first obtained for whole numbers n , retain a meaning when n is any number , positive or negative , whole or fractional or incommen ...
Side 25
... divide one another in the ratio 1 to 2 . ABC is any triangle , AL and CM two medians intersecting at O , to shew that BO produced passes through the mid - point N of AC . Let Then OA = a , LO = t1a OC = y , MO = t2y . BM = MA = t2y + a ...
... divide one another in the ratio 1 to 2 . ABC is any triangle , AL and CM two medians intersecting at O , to shew that BO produced passes through the mid - point N of AC . Let Then OA = a , LO = t1a OC = y , MO = t2y . BM = MA = t2y + a ...
Side 26
... divide one another in ratio . (光 + 号) Fig . 25 . ( iv ) Assuming that the bisector of the angle between the equal sides of an isosceles triangle bisects the base , we can easily obtain the vector bisecting the angle between any 26 ...
... divide one another in ratio . (光 + 号) Fig . 25 . ( iv ) Assuming that the bisector of the angle between the equal sides of an isosceles triangle bisects the base , we can easily obtain the vector bisecting the angle between any 26 ...
Side 27
... divides the base in the ratio of the sides . ABC is the triangle , BO the bisector of the angle at B , a the magnitude of BA , b that of BC . Then AB CB a + b = = tB . But AB = ẞ - t1a Fig . 26 . Hence tß = в - CB - B + tα . в t1 t2 a + ...
... divides the base in the ratio of the sides . ABC is the triangle , BO the bisector of the angle at B , a the magnitude of BA , b that of BC . Then AB CB a + b = = tB . But AB = ẞ - t1a Fig . 26 . Hence tß = в - CB - B + tα . в t1 t2 a + ...
Side 28
... divide AB , and ÂÂ1 in the same ratio , shew that OPQ is a straight line . ( 14 ) Any point P is joined to the vertices of a parallelogram , shew that the sum of the steps to the vertices is four times the step to the intersection of ...
... divide AB , and ÂÂ1 in the same ratio , shew that OPQ is a straight line . ( 14 ) Any point P is joined to the vertices of a parallelogram , shew that the sum of the steps to the vertices is four times the step to the intersection of ...
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Vectors and Rotors: With Applications Olaus Henrici,George Charles Turner Uten tilgangsbegrensning - 1903 |
Vanlige uttrykk og setninger
a₁ Algebra angle applied axis B₁ B₂ bars base beam bending bending moment bisect C₁ called centre collinear Commutative Law components compression coordinates coplanar corresponding definite denote determined diagonals direction and sense distance divide draw drawn equal equation equilibrium figure find the mass-centre forces acting frame friction geometrical girder give given points given rotors Hence the mass-centre horizontal length line joining line parallel link-polygon load m₁ magnitude mass mass-points mid-point momental area move negative number of vectors orts parallel rotors parallelogram parallelopiped perpendicular plane pole polygon position vector projection quantity reaction rectangle represent rigid body scalar product shearing force shew shewn sides straight line stress diagram string Suppose system of rotors tension tetrahedron theorem tons triangle vanishes vector product vector-polygon vertex vertices weight
Populære avsnitt
Side 21 - If two triangles have one angle of the one equal to one angle of the other and the sides about these equal angles proportional, the triangles are similar.
Side 29 - ... line and the extremities of the base have the same ratio which the other sides of the triangle have to one...
Side 8 - If a straight line be divided into any two parts, the square on the whole line is equal to the squares on the two parts, together with twice the rectangle contained by the two parts.
Side 112 - ... is equal to the rectangle contained by the segments of the other.
Side 17 - ... from the beginning of the first to the end of the last...