Mensuration for beginners [With] Answers1883 |
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Side
... Decimal Fractions . 3. Every variety of example is given under each subdivision ; the published Examination Papers of the London University ( Matriculation ) , the Education De- partment ( Pupil Teachers ' , Queen's Scholarship and ...
... Decimal Fractions . 3. Every variety of example is given under each subdivision ; the published Examination Papers of the London University ( Matriculation ) , the Education De- partment ( Pupil Teachers ' , Queen's Scholarship and ...
Side 7
... decimal of the highest . Another method sometimes adopted is called Duodecimals , or Cross Multiplication . We proceed to exemplify each method separately . 21. To find , by reduction , the area of a square when its side is given in ...
... decimal of the highest . Another method sometimes adopted is called Duodecimals , or Cross Multiplication . We proceed to exemplify each method separately . 21. To find , by reduction , the area of a square when its side is given in ...
Side 9
... decimal of the highest denomination , and multiply the result by itself ; the product will be the area expressed in the same denomination . Express the inches as a decimal part of a foot , only when it produces a finite decimal , as in ...
... decimal of the highest denomination , and multiply the result by itself ; the product will be the area expressed in the same denomination . Express the inches as a decimal part of a foot , only when it produces a finite decimal , as in ...
Side 10
... decimal of a square foot , the area of the squares whose sides are respectively : - ( 1 ) 18 ft . 6 in . ( 2 ) 29 ft . 3 in . ( 3 ) 34 ft . 9 in . ( 4 ) 6 ft . 11 in . ( 5 ) A square room is 15 ft . 9 in . long . Find the number of ...
... decimal of a square foot , the area of the squares whose sides are respectively : - ( 1 ) 18 ft . 6 in . ( 2 ) 29 ft . 3 in . ( 3 ) 34 ft . 9 in . ( 4 ) 6 ft . 11 in . ( 5 ) A square room is 15 ft . 9 in . long . Find the number of ...
Side 12
... decimal numbers , remove the point two places to the right . Ex . Reduce to links , 16 ch . , 16 ch . 5 lks . , 17.625 ch . 16 ch.1600 lks . 16 ch . 5 lks . = 1605 lks . 17.625 ch.1762.5 1ks . 30. To reduce links to chains . RULE ...
... decimal numbers , remove the point two places to the right . Ex . Reduce to links , 16 ch . , 16 ch . 5 lks . , 17.625 ch . 16 ch.1600 lks . 16 ch . 5 lks . = 1605 lks . 17.625 ch.1762.5 1ks . 30. To reduce links to chains . RULE ...
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Vanlige uttrykk og setninger
9 ft A B C D ABCD acres angle subtended Area of base broad centre circle circular circum Circumference of base contains cube cubic foot curved surface cwts cylinder depth diagonal diam Diameter of base equal equilateral triangle find the area Find the cost find the expense find the height find the length find the number Find the side find the volume following dimensions found by Art heptagon hexagon hypotenuse length of carpet Multiply number of cubic number of degrees papering a room parallel sides parallelopiped paving perimeter perpendicular distance perpendicular height polygon prism quotient Radius of base rectangle regular polygon Required the area rhomboid rhombus right cone right-angled triangle round RULE sector slant height solid content square chains square feet square field square links square pyramid square root square yard thick trapezium trapezoid triangular field whole surface width
Populære avsnitt
Side 18 - Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend.
Side 52 - A circle is a plane figure contained by one line, which is called the circumference, and is such, that all straight lines drawn from a certain point within the figure to the circumference are equal to one another.
Side 52 - A diameter of a circle is a straight line drawn through the centre, and terminated both ways by the circumference.
Side 41 - RULE. — Multiply half the sum of the two parallel sides by the perpendicular distance between them, and the product will be the area.
Side 45 - To find the area of a trapezium. RULE. — Divide the trapezium into two triangles by a diagonal, and then find the areas of these triangles ; their sum will be the area of the trapezium.
Side 103 - A SPHERE is a solid bounded by a curved surface, every part of which is equally distant from a point within, called the centre.
Side 101 - The area of the curved surface of a cone is equal to one-half the product of the slant hight by the circumference of the base (660).
Side 105 - A reservoir is 24 ft. 8 in. long, by 12 ft. 9 in. wide ; how many cubic feet of water must be drawn off to make the surface sink 1 foot?
Side 38 - RULE. from half the sum of the three sides, subtract each side separately; multiply the half sum and the three remainders together, and the square root of the product will be the area required.
Side 33 - A rhombus is that which has all its sides equal, but its angles are not right angles.