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Side 96
( 13 ) How much sheet - lead is used in lining the sides and bottom of a cubical
vessel containing 729 c . ft . of water ? [ The surface to be covered with lead
consists of five faces only . ) ( 14 ) A cubical cistern measures 5 ft . every way ;
find the ...
( 13 ) How much sheet - lead is used in lining the sides and bottom of a cubical
vessel containing 729 c . ft . of water ? [ The surface to be covered with lead
consists of five faces only . ) ( 14 ) A cubical cistern measures 5 ft . every way ;
find the ...
Side 101
... 2 ft . wide , with sheet lead of 10 lbs . to the square foot , estimating the lead at
Li 178 . 4d . per cwt . ? ( 7 ) How much gilding will be required for THE
RECTANGULAR PARALLELOPIPED . 101.
... 2 ft . wide , with sheet lead of 10 lbs . to the square foot , estimating the lead at
Li 178 . 4d . per cwt . ? ( 7 ) How much gilding will be required for THE
RECTANGULAR PARALLELOPIPED . 101.
Side 102
8 c . ft . of water ; how many square feet of lead will be required to line it ? ( 11 )
How many sheets of paper 8 in . by 6 in . will be required to cover the top and
sides of a box 3 ft . 6 in . long , 2 ft . 4 in . wide , and 1 ft . 6 in . deep ? ( 12 ) The
value ...
8 c . ft . of water ; how many square feet of lead will be required to line it ? ( 11 )
How many sheets of paper 8 in . by 6 in . will be required to cover the top and
sides of a box 3 ft . 6 in . long , 2 ft . 4 in . wide , and 1 ft . 6 in . deep ? ( 12 ) The
value ...
Side 113
( 5 ) A pyramid of lead is 18 in . high , and stands on a square base 5 in . long on
each side ; find its weight , a c . in . of lead weighing 6 . 6 ozs . ( 6 ) The base of a
pyramid is a rectangle 27 ft . long and 20 ft . broad ; its height is 15 ft . ; find the ...
( 5 ) A pyramid of lead is 18 in . high , and stands on a square base 5 in . long on
each side ; find its weight , a c . in . of lead weighing 6 . 6 ozs . ( 6 ) The base of a
pyramid is a rectangle 27 ft . long and 20 ft . broad ; its height is 15 ft . ; find the ...
Side 116
( 6 ) A square tower , 20 ft . on each side , has a pyramidal roof whose
perpendicular height is 24 ft . , covered with lead , at 1s . 6d . per sq . ft . ; find the
cost . ( 7 ) A square pyramidal stone whose perpendicular height is 16 ft . , and
each side of ...
( 6 ) A square tower , 20 ft . on each side , has a pyramidal roof whose
perpendicular height is 24 ft . , covered with lead , at 1s . 6d . per sq . ft . ; find the
cost . ( 7 ) A square pyramidal stone whose perpendicular height is 16 ft . , and
each side of ...
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ABCD acres angle subtended base breadth broad called centre circle circular circumference Circumference of base conical contains cover cube curved surface cylinder decimal deep denomination depth diagonal diam diameter Diameter of base difference Divide drawn edge ends equal expressed faces feet figure find the area Find the cost find the length find the side floor foot four given half Hence hexagonal inner lead measures miles Multiply outer parallel sides paving perimeter perpendicular distance perpendicular height piece plot poles polygon prism pyramid quotient radius Radius of base rectangle rectangular Reduce regular respectively right cone right-angled round RULE sector slant height solid content sphere square square feet square root square yard straight line thick trapezoid triangle triangular volume wall whole surface wide width yards
Populære avsnitt
Side 18 - Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend.
Side 62 - A circle is a plane figure contained by one line, which is called the circumference, and is such, that all straight lines drawn from a certain point within the figure to the circumference are equal to one another.
Side 62 - A diameter of a circle is a straight line drawn through the centre, and terminated both ways by the circumference.
Side 49 - RULE. — Multiply half the sum of the two parallel sides by the perpendicular distance between them, and the product will be the area.
Side 53 - To find the area of a trapezium. RULE. — Divide the trapezium into two triangles by a diagonal, and then find the areas of these triangles ; their sum will be the area of the trapezium.
Side 5 - A SPHERE is a solid bounded by a curved surface, every part of which is equally distant from a point within, called the centre.
Side 117 - The area of the curved surface of a cone is equal to one-half the product of the slant hight by the circumference of the base (660).
Side 7 - A reservoir is 24 ft. 8 in. long, by 12 ft. 9 in. wide ; how many cubic feet of water must be drawn off to make the surface sink 1 foot?
Side 38 - RULE. from half the sum of the three sides, subtract each side separately; multiply the half sum and the three remainders together, and the square root of the product will be the area required.
Side 33 - A rhombus is that which has all its sides equal, but its angles are not right angles.