## Mensuration for beginners [With] Answers |

### Inni boken

Resultat 1-5 av 18

Side 9

... of

3s . 9d . per square yard . 23 . To find , by decimals , the area of a square when its

side is given in different denominations . RULE . Express the length of the side ...

... of

**paving**a square courtyard , whose boundary wall measures 57 yds . 1 ft . , at3s . 9d . per square yard . 23 . To find , by decimals , the area of a square when its

side is given in different denominations . RULE . Express the length of the side ...

Side 16

Divide the greater space by the less , and the quotient will be the number

required . [ The areas must be both expressed in the same denomination . ] Ex .

How many square tiles 8 in . long will be required for

hall in the ...

Divide the greater space by the less , and the quotient will be the number

required . [ The areas must be both expressed in the same denomination . ] Ex .

How many square tiles 8 in . long will be required for

**paving**a college dining -hall in the ...

Side 17

How many flagstones , 23 ft . square , will be required for

square field , 387 . 5 yds . long , is divided into allotments , each 15 . 5 yds .

square . How many are there ? ( 5 ) How many square tiles , 15 in . long , will be

required for ...

How many flagstones , 23 ft . square , will be required for

**paving**it ? ( 4 ) Asquare field , 387 . 5 yds . long , is divided into allotments , each 15 . 5 yds .

square . How many are there ? ( 5 ) How many square tiles , 15 in . long , will be

required for ...

Side 20

Length of side = sq . root of 324 = 18 ft . Ex . XVI . ( 1 ) A square garden was sold

for £183 158 . If the land was valued at 3s . per sq . yd . , find the length of the

garden . ( 2 ) Find the length of the side of a square enclosure , the

Length of side = sq . root of 324 = 18 ft . Ex . XVI . ( 1 ) A square garden was sold

for £183 158 . If the land was valued at 3s . per sq . yd . , find the length of the

garden . ( 2 ) Find the length of the side of a square enclosure , the

**paving**of ... Side 23

( 35 ) Required the cost of a mahogany dining - table top , 14 ft . 3 in . long and 4

ft . 8 in . broad , at 1s . 8d . per sq . ft . ( 36 ) A rectangular enclosure is 32 yds . 2 ft

. 3 in . long , and 15 yds . 1 ft . 6 in . broad , what will it cost in

...

( 35 ) Required the cost of a mahogany dining - table top , 14 ft . 3 in . long and 4

ft . 8 in . broad , at 1s . 8d . per sq . ft . ( 36 ) A rectangular enclosure is 32 yds . 2 ft

. 3 in . long , and 15 yds . 1 ft . 6 in . broad , what will it cost in

**paving**at 6s . per sq...

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ABCD acres angle subtended base breadth broad called centre circle circular circumference Circumference of base conical contains cover cube curved surface cylinder decimal deep denomination depth diagonal diam diameter Diameter of base difference Divide drawn edge ends equal expressed faces feet figure find the area Find the cost find the length find the side floor foot four given half Hence hexagonal inner lead measures miles Multiply outer parallel sides paving perimeter perpendicular distance perpendicular height piece plot poles polygon prism pyramid quotient radius Radius of base rectangle rectangular Reduce regular respectively right cone right-angled round RULE sector slant height solid content sphere square square feet square root square yard straight line thick trapezoid triangle triangular volume wall whole surface wide width yards

### Populære avsnitt

Side 18 - Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend.

Side 62 - A circle is a plane figure contained by one line, which is called the circumference, and is such, that all straight lines drawn from a certain point within the figure to the circumference are equal to one another.

Side 62 - A diameter of a circle is a straight line drawn through the centre, and terminated both ways by the circumference.

Side 49 - RULE. — Multiply half the sum of the two parallel sides by the perpendicular distance between them, and the product will be the area.

Side 53 - To find the area of a trapezium. RULE. — Divide the trapezium into two triangles by a diagonal, and then find the areas of these triangles ; their sum will be the area of the trapezium.

Side 5 - A SPHERE is a solid bounded by a curved surface, every part of which is equally distant from a point within, called the centre.

Side 117 - The area of the curved surface of a cone is equal to one-half the product of the slant hight by the circumference of the base (660).

Side 7 - A reservoir is 24 ft. 8 in. long, by 12 ft. 9 in. wide ; how many cubic feet of water must be drawn off to make the surface sink 1 foot?

Side 38 - RULE. from half the sum of the three sides, subtract each side separately; multiply the half sum and the three remainders together, and the square root of the product will be the area required.

Side 33 - A rhombus is that which has all its sides equal, but its angles are not right angles.