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Side
By a happy use of the Diophantine Analysis , he has been able to give examples
on the Right - angled Triangle , and that bête noire of pupils , the Area of a
Triangle when the three sides are given , every one of which “ comes out without
a ...
By a happy use of the Diophantine Analysis , he has been able to give examples
on the Right - angled Triangle , and that bête noire of pupils , the Area of a
Triangle when the three sides are given , every one of which “ comes out without
a ...
Side 39
A right - angled triangle is one that has a right angle . A B is the hypotenuse , BO
is the base , and A C the perpendicular . AC and C B , which include the right
angle , are also called the sides of the right - angled 5 triangle . > Perpendicular .
A right - angled triangle is one that has a right angle . A B is the hypotenuse , BO
is the base , and A C the perpendicular . AC and C B , which include the right
angle , are also called the sides of the right - angled 5 triangle . > Perpendicular .
Side 40
To find the hypotenuse of a right - angled triangle when the sides are given .
RULE . Add the squares of the sides and extract the square root of the sum . The
annexed diagram represents a rightangled triangle , A B C , of which A B is the ...
To find the hypotenuse of a right - angled triangle when the sides are given .
RULE . Add the squares of the sides and extract the square root of the sum . The
annexed diagram represents a rightangled triangle , A B C , of which A B is the ...
Side 41
William Dodds. Cord . Tower . Ex . XXVII . Find the hypotenuse from the given
sides in the following right - angled triangles :( 1 ) 7 ft . , 24 ft . ( 5 ) 3 ft . 8 in . ; 40 ft
. 3 in . ( 2 ) 8 ft . , 15 ft . ( 6 ) 5 ft . 3 in . ; 1 ft . 4 in . ( 3 ) 30 yds . , 40 yds . ( 7 ) 3 yds .
William Dodds. Cord . Tower . Ex . XXVII . Find the hypotenuse from the given
sides in the following right - angled triangles :( 1 ) 7 ft . , 24 ft . ( 5 ) 3 ft . 8 in . ; 40 ft
. 3 in . ( 2 ) 8 ft . , 15 ft . ( 6 ) 5 ft . 3 in . ; 1 ft . 4 in . ( 3 ) 30 yds . , 40 yds . ( 7 ) 3 yds .
Side 42
To find one side of a right - angled triangle when the hypotenuse and the other
side are given . Rule . From the square of the hypotenuse subtract the square of
the given side , and extract the squaro root of the remainder . See Fig . Art . 71 .
To find one side of a right - angled triangle when the hypotenuse and the other
side are given . Rule . From the square of the hypotenuse subtract the square of
the given side , and extract the squaro root of the remainder . See Fig . Art . 71 .
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ABCD acres angle subtended base breadth broad called centre circle circular circumference Circumference of base conical contains cover cube curved surface cylinder decimal deep denomination depth diagonal diam diameter Diameter of base difference Divide drawn edge ends equal expressed faces feet figure find the area Find the cost find the length find the side floor foot four given half Hence hexagonal inner lead measures miles Multiply outer parallel sides paving perimeter perpendicular distance perpendicular height piece plot poles polygon prism pyramid quotient radius Radius of base rectangle rectangular Reduce regular respectively right cone right-angled round RULE sector slant height solid content sphere square square feet square root square yard straight line thick trapezoid triangle triangular volume wall whole surface wide width yards
Populære avsnitt
Side 18 - Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend.
Side 62 - A circle is a plane figure contained by one line, which is called the circumference, and is such, that all straight lines drawn from a certain point within the figure to the circumference are equal to one another.
Side 62 - A diameter of a circle is a straight line drawn through the centre, and terminated both ways by the circumference.
Side 49 - RULE. — Multiply half the sum of the two parallel sides by the perpendicular distance between them, and the product will be the area.
Side 53 - To find the area of a trapezium. RULE. — Divide the trapezium into two triangles by a diagonal, and then find the areas of these triangles ; their sum will be the area of the trapezium.
Side 5 - A SPHERE is a solid bounded by a curved surface, every part of which is equally distant from a point within, called the centre.
Side 117 - The area of the curved surface of a cone is equal to one-half the product of the slant hight by the circumference of the base (660).
Side 7 - A reservoir is 24 ft. 8 in. long, by 12 ft. 9 in. wide ; how many cubic feet of water must be drawn off to make the surface sink 1 foot?
Side 38 - RULE. from half the sum of the three sides, subtract each side separately; multiply the half sum and the three remainders together, and the square root of the product will be the area required.
Side 33 - A rhombus is that which has all its sides equal, but its angles are not right angles.