Mensuration for beginners [With] Answers |
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Resultat 1-5 av 27
Side 4
[ Reduce the sq . yds . to acres . 4810 sq . yds . = 1 acre . ] ( 11 ) A square field is
193 yds . long , how many acres are there in it ? ( 12 ) Find the area of a square
whose perimeter is 256 yds . [ The perimeter of a square is the distance round it .
[ Reduce the sq . yds . to acres . 4810 sq . yds . = 1 acre . ] ( 11 ) A square field is
193 yds . long , how many acres are there in it ? ( 12 ) Find the area of a square
whose perimeter is 256 yds . [ The perimeter of a square is the distance round it .
Side 5
A square plot of ground , EFGH , whose side E F is 50 yds . long , has a gravel
walk 2 yds . wide running round the outside of it . What is the area of the walk ?
Here , length of inner square = 50 yds . , outer = 54 yds . Hence , area of outer ...
A square plot of ground , EFGH , whose side E F is 50 yds . long , has a gravel
walk 2 yds . wide running round the outside of it . What is the area of the walk ?
Here , length of inner square = 50 yds . , outer = 54 yds . Hence , area of outer ...
Side 6
( 5 ) From a square lawn 32 ft . long , a flower - border 3 ft . wide is taken off all
round ; find the area of the border . ( 6 ) A square court is 60 ft . long , and a path
6 ft . wide goes ronnd the court inside it ; find how many tiles a foot square will be
...
( 5 ) From a square lawn 32 ft . long , a flower - border 3 ft . wide is taken off all
round ; find the area of the border . ( 6 ) A square court is 60 ft . long , and a path
6 ft . wide goes ronnd the court inside it ; find how many tiles a foot square will be
...
Side 10
Find the number of square feet in the floor and ceiling together . ( 6 ) The side of a
square is 12 yds . 1 ft . 6 in . , and a path 10 ft . 6 in . wide goes round the square
outside it . Find the number of tiles one foot square required to pave the path .
Find the number of square feet in the floor and ceiling together . ( 6 ) The side of a
square is 12 yds . 1 ft . 6 in . , and a path 10 ft . 6 in . wide goes round the square
outside it . Find the number of tiles one foot square required to pave the path .
Side 19
... is 133225 sq . yds . find its perimeter . 113 ) A square deer - park , including
1600 acres of land and a lake of 960 acres , is to be enclosed with a wall ; what
will be its length in yards ? ( 14 ) A man undertook to run round a THE SQUARE .
19.
... is 133225 sq . yds . find its perimeter . 113 ) A square deer - park , including
1600 acres of land and a lake of 960 acres , is to be enclosed with a wall ; what
will be its length in yards ? ( 14 ) A man undertook to run round a THE SQUARE .
19.
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Vanlige uttrykk og setninger
ABCD acres angle subtended base breadth broad called centre circle circular circumference Circumference of base conical contains cover cube curved surface cylinder decimal deep denomination depth diagonal diam diameter Diameter of base difference Divide drawn edge ends equal expressed faces feet figure find the area Find the cost find the length find the side floor foot four given half Hence hexagonal inner lead measures miles Multiply outer parallel sides paving perimeter perpendicular distance perpendicular height piece plot poles polygon prism pyramid quotient radius Radius of base rectangle rectangular Reduce regular respectively right cone right-angled round RULE sector slant height solid content sphere square square feet square root square yard straight line thick trapezoid triangle triangular volume wall whole surface wide width yards
Populære avsnitt
Side 18 - Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend.
Side 62 - A circle is a plane figure contained by one line, which is called the circumference, and is such, that all straight lines drawn from a certain point within the figure to the circumference are equal to one another.
Side 62 - A diameter of a circle is a straight line drawn through the centre, and terminated both ways by the circumference.
Side 49 - RULE. — Multiply half the sum of the two parallel sides by the perpendicular distance between them, and the product will be the area.
Side 53 - To find the area of a trapezium. RULE. — Divide the trapezium into two triangles by a diagonal, and then find the areas of these triangles ; their sum will be the area of the trapezium.
Side 5 - A SPHERE is a solid bounded by a curved surface, every part of which is equally distant from a point within, called the centre.
Side 117 - The area of the curved surface of a cone is equal to one-half the product of the slant hight by the circumference of the base (660).
Side 7 - A reservoir is 24 ft. 8 in. long, by 12 ft. 9 in. wide ; how many cubic feet of water must be drawn off to make the surface sink 1 foot?
Side 38 - RULE. from half the sum of the three sides, subtract each side separately; multiply the half sum and the three remainders together, and the square root of the product will be the area required.
Side 33 - A rhombus is that which has all its sides equal, but its angles are not right angles.
Bibliografisk informasjon
| Tittel | Mensuration for beginners [With] Answers Mensuration for beginners [With] Answers, William Dodds |
| Forfatter | William Dodds |
| distribuert | 1883 |
| Original fra | Oxford University |
| Digitalisert | 8. sep 2006 |
| Eksporter sitat | BiBTeX EndNote RefMan |