## Mensuration for beginners [With] Answers |

### Inni boken

Resultat 1-5 av 13

Side 37

( 10 ) A

height 72 yds . 1 ft . is to be paved at the rate of 18 . 6d . per sq . yd . ; find the

expense . ( 11 ) A

height ...

( 10 ) A

**triangular**plot of ground whose base is 85 yds . 2 ft . and perpendicularheight 72 yds . 1 ft . is to be paved at the rate of 18 . 6d . per sq . yd . ; find the

expense . ( 11 ) A

**triangular**field whose base is 850 links and perpendicularheight ...

Side 38

( 1 ) A

height . ( 2 ) An enclosure in the form of an equilateral triangle is paved at the rate

of 9d . per sq . foot . Its perimeter is 63 yds . , and the cost of paving the whole £35

...

( 1 ) A

**triangular**field contains 34 acres , and its base is 1750 links , find theheight . ( 2 ) An enclosure in the form of an equilateral triangle is paved at the rate

of 9d . per sq . foot . Its perimeter is 63 yds . , and the cost of paving the whole £35

...

Side 39

( 13 ) Find the area of a triangle whose sides are 3 . 27 ft . , 4 . 36 ft . , and 5 . 45 ft

. ( 14 ) Find the area in acres , roods , and poles , of a

sides are 300 Iks . , 975 Iks . , and 1125 lks . ( 15 ) Find the area of a triangle

whose ...

( 13 ) Find the area of a triangle whose sides are 3 . 27 ft . , 4 . 36 ft . , and 5 . 45 ft

. ( 14 ) Find the area in acres , roods , and poles , of a

**triangular**field , whosesides are 300 Iks . , 975 Iks . , and 1125 lks . ( 15 ) Find the area of a triangle

whose ...

Side 44

( 17 ) Find the rent of a

perpendicular 2 chs . 50 lks . , at £4 per acro . ( 18 ) A church and chapel stand

opposite each MENSURATION FOR BEGINNERS . Miscellaneous Examples.

( 17 ) Find the rent of a

**triangular**field whose base is 12 chs . 85 Iks . , andperpendicular 2 chs . 50 lks . , at £4 per acro . ( 18 ) A church and chapel stand

opposite each MENSURATION FOR BEGINNERS . Miscellaneous Examples.

Side 48

( 66 ) The paving of a

sides was 126 ft . , and the length of each of the other two equal sides was 105 ft .

: find the price of paving per sq . yd . Butler & Tanger , The Selwood Printing Wo ...

( 66 ) The paving of a

**triangular**court cost £18 78 . 6d . ; the longest of the threesides was 126 ft . , and the length of each of the other two equal sides was 105 ft .

: find the price of paving per sq . yd . Butler & Tanger , The Selwood Printing Wo ...

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ABCD acres angle subtended base breadth broad called centre circle circular circumference Circumference of base conical contains cover cube curved surface cylinder decimal deep denomination depth diagonal diam diameter Diameter of base difference Divide drawn edge ends equal expressed faces feet figure find the area Find the cost find the length find the side floor foot four given half Hence hexagonal inner lead measures miles Multiply outer parallel sides paving perimeter perpendicular distance perpendicular height piece plot poles polygon prism pyramid quotient radius Radius of base rectangle rectangular Reduce regular respectively right cone right-angled round RULE sector slant height solid content sphere square square feet square root square yard straight line thick trapezoid triangle triangular volume wall whole surface wide width yards

### Populære avsnitt

Side 18 - Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend.

Side 62 - A circle is a plane figure contained by one line, which is called the circumference, and is such, that all straight lines drawn from a certain point within the figure to the circumference are equal to one another.

Side 62 - A diameter of a circle is a straight line drawn through the centre, and terminated both ways by the circumference.

Side 49 - RULE. — Multiply half the sum of the two parallel sides by the perpendicular distance between them, and the product will be the area.

Side 53 - To find the area of a trapezium. RULE. — Divide the trapezium into two triangles by a diagonal, and then find the areas of these triangles ; their sum will be the area of the trapezium.

Side 5 - A SPHERE is a solid bounded by a curved surface, every part of which is equally distant from a point within, called the centre.

Side 117 - The area of the curved surface of a cone is equal to one-half the product of the slant hight by the circumference of the base (660).

Side 7 - A reservoir is 24 ft. 8 in. long, by 12 ft. 9 in. wide ; how many cubic feet of water must be drawn off to make the surface sink 1 foot?

Side 38 - RULE. from half the sum of the three sides, subtract each side separately; multiply the half sum and the three remainders together, and the square root of the product will be the area required.

Side 33 - A rhombus is that which has all its sides equal, but its angles are not right angles.