Mensuration for beginners [With] Answers1883 |
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Resultat 1-5 av 20
Side 6
... whole picture when framed , and of the surface to be gilded . 19. To find the value of any square surface when the side is given . RULE . Find the area of the square , and multiply the number of square units in it by the value of a ...
... whole picture when framed , and of the surface to be gilded . 19. To find the value of any square surface when the side is given . RULE . Find the area of the square , and multiply the number of square units in it by the value of a ...
Side 20
... all round at 74d . per foot . ( 16 ) A square plot of land is 55 links in length ; what is the side of another plot of ... whole surface by the value of a square unit , and the quotient will be the number of square units in the area . 20 ...
... all round at 74d . per foot . ( 16 ) A square plot of land is 55 links in length ; what is the side of another plot of ... whole surface by the value of a square unit , and the quotient will be the number of square units in the area . 20 ...
Side 29
... whole expense may be the same as for the Brussels carpet . [ Area of room ... all round the carpet . How much per sq . ft . does the margin cost to paint ... surface of the walls of a room . RULE . Multiply the distance round the room ...
... whole expense may be the same as for the Brussels carpet . [ Area of room ... all round the carpet . How much per sq . ft . does the margin cost to paint ... surface of the walls of a room . RULE . Multiply the distance round the room ...
Side 31
... total area of the wall - surface by the width of the paper , and the quotient will be the length required . Ex . Find the expense of papering a room 20 ft . long , 15 ft . broad , and 12 ft . high , with paper 2 ft . wide at 6d . per yd ...
... total area of the wall - surface by the width of the paper , and the quotient will be the length required . Ex . Find the expense of papering a room 20 ft . long , 15 ft . broad , and 12 ft . high , with paper 2 ft . wide at 6d . per yd ...
Side 37
... whole triangle ABC is equal to half the rectangle EBCF . Hence it follows that the area of a triangle is equal to ... surface , hence area of triangle ABC = 56 ÷ 2 = 28 sq . ft . Ex . XXIV . Find the areas of the triangles having the ...
... whole triangle ABC is equal to half the rectangle EBCF . Hence it follows that the area of a triangle is equal to ... surface , hence area of triangle ABC = 56 ÷ 2 = 28 sq . ft . Ex . XXIV . Find the areas of the triangles having the ...
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Vanlige uttrykk og setninger
9 ft A B C D ABCD acres angle subtended Area of base broad centre circle circular circum Circumference of base contains cube cubic foot curved surface cwts cylinder depth diagonal diam Diameter of base equal equilateral triangle find the area Find the cost find the expense find the height find the length find the number Find the side find the volume following dimensions found by Art heptagon hexagon hypotenuse length of carpet Multiply number of cubic number of degrees papering a room parallel sides parallelopiped paving perimeter perpendicular distance perpendicular height polygon prism quotient Radius of base rectangle regular polygon Required the area rhomboid rhombus right cone right-angled triangle round RULE sector slant height solid content square chains square feet square field square links square pyramid square root square yard thick trapezium trapezoid triangular field whole surface width
Populære avsnitt
Side 18 - Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend.
Side 52 - A circle is a plane figure contained by one line, which is called the circumference, and is such, that all straight lines drawn from a certain point within the figure to the circumference are equal to one another.
Side 52 - A diameter of a circle is a straight line drawn through the centre, and terminated both ways by the circumference.
Side 41 - RULE. — Multiply half the sum of the two parallel sides by the perpendicular distance between them, and the product will be the area.
Side 45 - To find the area of a trapezium. RULE. — Divide the trapezium into two triangles by a diagonal, and then find the areas of these triangles ; their sum will be the area of the trapezium.
Side 103 - A SPHERE is a solid bounded by a curved surface, every part of which is equally distant from a point within, called the centre.
Side 101 - The area of the curved surface of a cone is equal to one-half the product of the slant hight by the circumference of the base (660).
Side 105 - A reservoir is 24 ft. 8 in. long, by 12 ft. 9 in. wide ; how many cubic feet of water must be drawn off to make the surface sink 1 foot?
Side 38 - RULE. from half the sum of the three sides, subtract each side separately; multiply the half sum and the three remainders together, and the square root of the product will be the area required.
Side 33 - A rhombus is that which has all its sides equal, but its angles are not right angles.