Mensuration for beginners [With] Answers |
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Side 6
Find the area of the whole picture when framed , and of the surface to be gilded .
19 . To find the value of any square surface when the side is given . RULE . Find
the area of the square , and multiply the number of square units in it by the value
...
Find the area of the whole picture when framed , and of the surface to be gilded .
19 . To find the value of any square surface when the side is given . RULE . Find
the area of the square , and multiply the number of square units in it by the value
...
Side 20
Divide the value of the whole surface by the value of a square unit , and the
quotient will be the number of square units in the area . 20 . Extract the square
root of this number , and the result will give the number of linear units in the side .
Divide the value of the whole surface by the value of a square unit , and the
quotient will be the number of square units in the area . 20 . Extract the square
root of this number , and the result will give the number of linear units in the side .
Side 29
Find the cost of the drugget per yd . so that the whole expense may be the same
as for the Brussels carpet . [ Area of room = 40 x 28 = 1120 sq . ft . ... To find the
area of the surface of the walls of a room . RULE . Multiply the distance round the
...
Find the cost of the drugget per yd . so that the whole expense may be the same
as for the Brussels carpet . [ Area of room = 40 x 28 = 1120 sq . ft . ... To find the
area of the surface of the walls of a room . RULE . Multiply the distance round the
...
Side 31
Find the whole cost of plastering the walls at 1s . , and the ceiling at 1s . 6d . per
sq . yd . ( 9 ) Find the ... Divide the total area of the wall - surface by the width of
the paper , and the quotient will be the length required . Ex . Find the expense of
...
Find the whole cost of plastering the walls at 1s . , and the ceiling at 1s . 6d . per
sq . yd . ( 9 ) Find the ... Divide the total area of the wall - surface by the width of
the paper , and the quotient will be the length required . Ex . Find the expense of
...
Side 37
Therefore the whole triangle ABC is equal to half the rectangle E BOF . Hence it
follows ... Area of rectangle E BCF = 8X7 = 56 sq . ft . , but the triangle A B C
contains half this surface , hence area of triangle ABC 56 ; 2 = 28 sq . ft . Ex . XXIV
.
Therefore the whole triangle ABC is equal to half the rectangle E BOF . Hence it
follows ... Area of rectangle E BCF = 8X7 = 56 sq . ft . , but the triangle A B C
contains half this surface , hence area of triangle ABC 56 ; 2 = 28 sq . ft . Ex . XXIV
.
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Vanlige uttrykk og setninger
ABCD acres angle subtended base breadth broad called centre circle circular circumference Circumference of base conical contains cover cube curved surface cylinder decimal deep denomination depth diagonal diam diameter Diameter of base difference Divide drawn edge ends equal expressed faces feet figure find the area Find the cost find the length find the side floor foot four given half Hence hexagonal inner lead measures miles Multiply outer parallel sides paving perimeter perpendicular distance perpendicular height piece plot poles polygon prism pyramid quotient radius Radius of base rectangle rectangular Reduce regular respectively right cone right-angled round RULE sector slant height solid content sphere square square feet square root square yard straight line thick trapezoid triangle triangular volume wall whole surface wide width yards
Populære avsnitt
Side 18 - Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend.
Side 62 - A circle is a plane figure contained by one line, which is called the circumference, and is such, that all straight lines drawn from a certain point within the figure to the circumference are equal to one another.
Side 62 - A diameter of a circle is a straight line drawn through the centre, and terminated both ways by the circumference.
Side 49 - RULE. — Multiply half the sum of the two parallel sides by the perpendicular distance between them, and the product will be the area.
Side 53 - To find the area of a trapezium. RULE. — Divide the trapezium into two triangles by a diagonal, and then find the areas of these triangles ; their sum will be the area of the trapezium.
Side 5 - A SPHERE is a solid bounded by a curved surface, every part of which is equally distant from a point within, called the centre.
Side 117 - The area of the curved surface of a cone is equal to one-half the product of the slant hight by the circumference of the base (660).
Side 7 - A reservoir is 24 ft. 8 in. long, by 12 ft. 9 in. wide ; how many cubic feet of water must be drawn off to make the surface sink 1 foot?
Side 38 - RULE. from half the sum of the three sides, subtract each side separately; multiply the half sum and the three remainders together, and the square root of the product will be the area required.
Side 33 - A rhombus is that which has all its sides equal, but its angles are not right angles.
Bibliografisk informasjon
| Tittel | Mensuration for beginners [With] Answers Mensuration for beginners [With] Answers, William Dodds |
| Forfatter | William Dodds |
| distribuert | 1883 |
| Original fra | Oxford University |
| Digitalisert | 8. sep 2006 |
| Eksporter sitat | BiBTeX EndNote RefMan |