 | Thomas Keith - 1810 - 478 sider
...these four logarithms, is the logarithmical sine of half the angle sought. (H. 215.) OR, RULE III. From half the sum of the three sides subtract each side separately. Then add together, The logarithmica! co-secants of half the sum of the sides, and of the difference... | |
 | Andrew Mackay - 1811 - 162 sider
...easily measured by the above method. In this case, therefore, the three sides are to be measured. Now from half the sum of the th'ree sides, subtract each side separately; then extract the square root of the product of half the sum of the sides by the three differences ;... | |
 | Edward Riddle - 1824 - 572 sider
...cases, we have the following rules. To find any angle of a spherical triangle when the three sides are given. RULE 1. From half the sum of the three sides subtract the side opposite to the required angle, then add together the log cosecants of the other two sides,... | |
 | Thomas Keith - 1826 - 504 sider
...these four logarithms, is the logarithmical sine of half the angle sought. (F. 184.) OR, RULE III. From half the sum of the three sides subtract each side separately. Then add together, The logarithmical co-secants of half the sum of the sides, and of the difference... | |
 | John Bonnycastle - 1829 - 256 sider
...and height 10.25? Ans. 102. 5/e. PROBLEM III. To find the area of a triangle whose three sides only are given. RULE.* . 1 . From half the sum of the three sides subtract each side severally. * Demon. Let AC— a, ±3=b, uc=c, and AD=a:; (See preceding fig.) Then, since BD=&— x,... | |
 | Ira Wanzer - 1831 - 408 sider
...in Problem III. 2. When the three sides of the triangle are given, the area may be found as follows: From half the sum of the three sides subtract each side separately ; then multiply the said half sum and the three remainders continually together, and the square root... | |
 | Ireland commissioners of nat. educ - 1834 - 370 sider
...feet Gi inches. PROBLEM V. Having the three sides of any Triangle given, to find its orea. RULE I. From, half the sum of the three sides subtract each side separately, then multiply the half sum and the three remainders together, and the square root of the last product... | |
 | Commissioners of National Education in Ireland - 1837 - 284 sider
...feet 6^ inches. PROBLEM V. Having the three sides of any Triangle given, to find its area. RULE I. From half the sum of the three sides subtract each side separately, then multiply the half sum and the three remainders together, and the square root of the last product... | |
 | Thomas Keith - 1839 - 498 sider
...the sum of these four logarithms is the logarithmic sine of half the angle sought (422). RULE III. From half the sum of the three sides subtract each side separately. Then add together, mic sines of the difference between the half sum and each side containing the required... | |
 | John Hind - 1840 - 252 sider
...Triangle. The area is equal to half the product of the base and the perpendicular altitude. (3) Triangle. From half the sum of the three sides, subtract each side separately: multiply together the half-sum and the three remainders, and the square root of the product will be... | |
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RULE. from half the sum of the three sides, subtract each side separately; multiply the half sum and the three remainders together, and the square root of the product will be the area required. 
