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" RULE. — Multiply half the sum of the two parallel sides by the perpendicular distance between them, and the product will be the area. "
Mensuration for beginners [With] Answers - Side 49
av William Dodds - 1883
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Mathematics: Compiled from the Best Authors and Intended to be the ..., Volum 2

1801 - 426 sider
...street. • t Ans. 76- 1 2333 35 feet. PROBLEM IV. 7o f:nd tlie area of a trapezoid. • RULE.* Multiply the sum of the two parallel sides by the perpendicular distance between them, and half the product will be the area. • EXAMPLES. * DEMONSTRATION. or (because B»=DE) =-, .-. A ABD+...
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A System of Geometry and Trigonometry: Together with a Treatise on Surveying ...

Abel Flint - 1804 - 168 sider
...and 8925X0.47076=4201 the double Area of the Triangle. PROBLEM X. To find the Area of a Trapezoid. RULE. Multiply half the Sum of the two parallel Sides by the perpendicular distance between them, or the Sum of the two parallel Sides by half the perpendicular distance ; the Product will be the Area....
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A System of Geometry and Trigonometry: Together with a Treatise on Surveying ...

Abel Flint - 1808 - 168 sider
...8925x0.47076=4201 the double Area of the Triangle. • PROBLEM X. To find the Area of a Trapezoid. RULE. Multiply half the Sum of the two parallel Sides by the perpendicular distance between them, or the sum of the two parallel Sides by half the perpendicular distance ; the Product will be the Area....
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The principles of architecture, Volum 1

Peter Nicholson - 1809
...42 504=the area of ABCD. PROBLEM VI. To find the area of a trapezoid. Multiply the half sum of the parallel sides by the perpendicular distance between them, and the product will be the area. EXAMPLE I. What is fhe area of a board or plank in the form of a trapeziod, being 1f. 7i. one end,...
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The complete measurer: or, The whole art of measuring, containing the ...

Thomas Keith - 1817
...17•6327 acres; or 17 acres. <• 2 roods 21 perches. PROBLEM VIII. • To find the Area of a Trapezoid. RULE *. Multiply half the sum of the two parallel...distance between them, and the product will be the area. Example 1. Let AB c D JE. be a trapezoid, the side '-. A )•. — 23, D c = 9•5, and CI — 13,...
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The new practical gager

Matthew Iley - 1820
...Quadrilateral wherein two unequal Sides are Parallel to one another. RULE. Multiply half the sum of the parallel sides by the perpendicular distance between them, and the product will be the area. Let ABCD be a quadrilateral, wherein AC and BD are parallel but unequal; and let EF, the perpendicular...
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A Treatise on Practical Gauging

Anthony Nesbit, W. Little - 1822
...Ant. 97.3383 bushels. PROBLEM VII. To Jind the area of a trapezoid. RULE. • By the Pen. Multiply the sum of the two parallel sides by the perpendicular distance between them, and half the product will be the area in square inches. Divide this area by 2 82, 231, and 2150.42, and...
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A System of Geometry and Trigonometry: Together with a Treatise on Surveying ...

Abel Flint - 1825 - 241 sider
...and 8925 X 0.47076=4201 tbe double Area of the Triangle. PROBLEM X. To find the Jbeaof a TrapezoiA. RULE. Multiply half the Sum of the two parallel Sides by the perpendicular distance between them, or the sum of the two parallel Sides by half the perpendicular distance, the product will be the Area....
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A Popular Course of Pure and Mixed Mathematics ...: With Tables of ...

Peter Nicholson - 1825 - 372 sider
...the arca of ABCD. MENSURATION. Prob. 6. To find the area of a trapezoid. Multiply the half sum of the parallel sides by the perpendicular distance between them, and the product will be the area. Ex. 3. What is the area of a board or plank in the form of a trapezoid, being If. 7¡- at one end,...
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The Operative Mechanic, and British Machinist: Being a Practical Display of ...

John Nicholson - 1825 - 795 sider
...square 63 I 189 of AB has been subtracted. 3 I 189 Prob. 4. To find the Area of aTrapezoid. Multiply the sum of the two parallel sides by the perpendicular distance between them, and half the product will be the area. Ex. In a trapezoid, the parallel sides are AB 7, and CD 12, and...
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