The Elements of Euclid for the Use of Schools and Colleges: Comprising the First Six Books and Portions of the Eleventh and Twelfth Books : with Notes, an Appendix, and ExercisesMacmillan, 1867 - 400 sider |
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Side 39
... ABCD , EBCF be on the same base BC , and between the same parallels AF , BC : the paral- lelogram ABCD shall be equal to the parallelogram EBCF . If the sides AD , DF of the parallelograms ABCD , DBCF , opposite to the base BC , be ...
... ABCD , EBCF be on the same base BC , and between the same parallels AF , BC : the paral- lelogram ABCD shall be equal to the parallelogram EBCF . If the sides AD , DF of the parallelograms ABCD , DBCF , opposite to the base BC , be ...
Side 40
... ABCD , EFGH be parallelograms on equal bases BC , FG , and between the same parallels AH , BG : the parallelogram ABCD shall be equal to the parallelogram EFGH . Join BE , CH . Then , because BC is equal to FG , [ Hyp . D E H and FG to ...
... ABCD , EFGH be parallelograms on equal bases BC , FG , and between the same parallels AH , BG : the parallelogram ABCD shall be equal to the parallelogram EFGH . Join BE , CH . Then , because BC is equal to FG , [ Hyp . D E H and FG to ...
Side 43
... ABCD and the triangle EBC be on the same base BC , and between the same parallels BC , AE : the parallelogram ABCD shall be double of tho triangle EBC . Join AC . Then the triangle ABC is equal to the triangle EBC , because they are on ...
... ABCD and the triangle EBC be on the same base BC , and between the same parallels BC , AE : the parallelogram ABCD shall be double of tho triangle EBC . Join AC . Then the triangle ABC is equal to the triangle EBC , because they are on ...
Side 45
... ABCD be a parallelogram , of which the diameter is AC ; and EH , GF parallelograms about AC , that is , through which AC passes ; and BK , KD the other paral- lelograms which make up the whole figure ABCD , and which are therefore ...
... ABCD be a parallelogram , of which the diameter is AC ; and EH , GF parallelograms about AC , that is , through which AC passes ; and BK , KD the other paral- lelograms which make up the whole figure ABCD , and which are therefore ...
Side 47
... ABCD be the given rectilineal figure , and E the given rectilineal angle : it is required to describe a par- allelogram equal to ABCD , and having an angle equal to E. F G B K H M Join DB , and describe the parallelogram FH equal to the ...
... ABCD be the given rectilineal figure , and E the given rectilineal angle : it is required to describe a par- allelogram equal to ABCD , and having an angle equal to E. F G B K H M Join DB , and describe the parallelogram FH equal to the ...
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The Elements of Euclid for the Use of Schools and Colleges Isaac Todhunter Uten tilgangsbegrensning - 1872 |
The Elements of Euclid for the Use of Schools and Colleges: Comprising the ... Euclid,Isaac Todhunter Uten tilgangsbegrensning - 1884 |
The Elements of Euclid for the Use of Schools and Colleges: Comprising the ... Euclid,Isaac Todhunter Uten tilgangsbegrensning - 1867 |
Vanlige uttrykk og setninger
ABCD AC is equal angle ABC angle ACB angle BAC angle EDF angles equal Axiom base BC bisects the angle centre chord circle ABC circle described circumference Construction Corollary describe a circle diameter double draw a straight equal angles equal to F equiangular equilateral equimultiples Euclid Euclid's Elements exterior angle given circle given point given straight line gnomon Hypothesis inscribed intersect isosceles triangle less Let ABC magnitudes middle point multiple opposite angles opposite sides parallelogram perpendicular plane polygon produced proportionals PROPOSITION 13 Q.E.D. PROPOSITION quadrilateral rectangle contained rectilineal figure remaining angle rhombus right angles right-angled triangle segment shew shewn side BC square on AC straight line &c straight line drawn tangent THEOREM touches the circle triangle ABC triangle DEF twice the rectangle vertex Wherefore
Populære avsnitt
Side 35 - IF a side of any triangle be produced, the exterior angle is equal to the two interior and opposite angles ; and the three interior angles of every triangle are equal to two right angles.
Side 67 - In obtuse-angled triangles, if a perpendicular be drawn from either of the acute angles to the opposite side produced, the square on the side subtending the obtuse angle, is greater than the squares on the sides containing the obtuse angle, by twice the rectangle contained by the side upon which, when produced, the perpendicular falls, and the straight line intercepted without the triangle between the perpendicular and the obtuse angle, Let ABC be an obtuse-angled triangle, having the obtuse angle...
Side 73 - When a straight line standing on another straight line makes the adjacent angles equal to one another, each of the angles is called a Right Angle; and the straight line which stands on the other is called a Perpendicular to it.
Side 284 - If two triangles have one angle of the one equal to one angle of the other and the sides about these equal angles proportional, the triangles are similar.
Side 50 - In any right-angled triangle, the square which is described upon the side subtending the right angle, is equal to the squares described upon the sides which contain the right angle.
Side 57 - If a straight line be divided into two equal parts, and also into two unequal parts ; the rectangle contained by the unequal parts, together with the square on the line between the points of section, is equal to the square on half the line.
Side 10 - THE angles at the base of an isosceles triangle are equal to one another : and, if the equal sides be produced, the angles upon the other side of the base shall be equal.
Side 227 - If two straight lines be at right angles to the same plane, they shall be parallel to one another. Let the straight lines AB, CD be at right angles to the same plane : AB is parallel to CD.
Side 102 - The angle in a semicircle is a right angle; the angle in a segment greater than a semicircle is less than a right angle; and the angle in a segment less than a semicircle is greater than a right angle.
Side 352 - Prove that the square on any straight line drawn from the vertex of an isosceles triangle to the base, is less than the square on a side of the triangle by the rectangle contained by the segments of the base : and conversely.