Solutions of the problems and riders proposed in the Senate-house examination for 1854, by the moderators and examiners |
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Side 9
... spaces , the line joining them will be parallel to the line joining them before they fell , that is , to the line of projection . Therefore , in the actual motion , the line joining them will be always parallel to the line of projection ...
... spaces , the line joining them will be parallel to the line joining them before they fell , that is , to the line of projection . Therefore , in the actual motion , the line joining them will be always parallel to the line of projection ...
Side 9
... spaces , the line joining them will be parallel to the line joining them before they fell , that is , to the line of projection . Therefore , in the actual motion , the line joining them will be always parallel to the line of projection ...
... spaces , the line joining them will be parallel to the line joining them before they fell , that is , to the line of projection . Therefore , in the actual motion , the line joining them will be always parallel to the line of projection ...
Side 9
... space there exists a system of such axes . Shew that in general there is only one point for which the principal axes are parallel to those drawn through a given point ; but that , if the given point be in one of the principal planes ...
... space there exists a system of such axes . Shew that in general there is only one point for which the principal axes are parallel to those drawn through a given point ; but that , if the given point be in one of the principal planes ...
Side 32
... space m times as great as W in the same time ; and after P is replaced by Q , Q must describe m times the space described by W in the same time ; therefore the whole accelerating force on Q must be m times as great as that on W. Let T ...
... space m times as great as W in the same time ; and after P is replaced by Q , Q must describe m times the space described by W in the same time ; therefore the whole accelerating force on Q must be m times as great as that on W. Let T ...
Side 35
... tube coincides for a certain space , must be tangents to the free portions of the elastic tube : the circular arc GH is therefore a quadrant . the pressure of the air within . Join OG , D2 9-12 . ] 35 PROBLEMS . at their intersection ...
... tube coincides for a certain space , must be tangents to the free portions of the elastic tube : the circular arc GH is therefore a quadrant . the pressure of the air within . Join OG , D2 9-12 . ] 35 PROBLEMS . at their intersection ...
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Solutions of the Problems and Riders Proposed in the Senate-House ... Exam Papers Cambridge Univ Ingen forhåndsvisning tilgjengelig - 2016 |
Vanlige uttrykk og setninger
angular velocity asymptote axes c₁ Cambridge catenary centre of force centre of gravity chord circle cloth conic section constant cos² cose cosẞ cota cotß Crown 8vo curvature curve cylinder denoting described diameter direction distance dx dy dx² ecliptic ellipse equal equation equilibrium Fellow of St fixed point fluid geometrical progression given Hence horizontal hyperbola inclined inclined plane intersection lamina latus rectum length locus longitude M.A. Fellow major axis middle point motion node orbit parabola parallel particle passing perpendicular plane plate position pressure prove radius refraction right angles ring shew sides Similarly sine sino sinẞ straight line string Supposing surface tana tangent tanß triangle Trinity College tube V₁ vertical
Populære avsnitt
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Side 169 - AB into two parts, so that the rectangle contained by the whole line and one of the parts, shall be equal to the square on the other part.
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Side 169 - To describe an isosceles triangle, having each of the angles at the base double of the third angle.