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Bøker Bok 110 av 12J of the square of their difference, then multiply by the hight, and divide as in...
" J of the square of their difference, then multiply by the hight, and divide as in the last rule. Having the diameter of a circle given, to find the area. RULE. — Multiply half the diameter by half the circumference, and the product is the area ; or,... "
The Theory and Practice of Gauging: Demonstrated in a Short and Easy Method ... - Side 97
av Robert Shirtcliffe - 1740 - 283 sider
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Sherwin's Mathematical Tables: Contrived in an Easy and Comprehensive Manner ...

Henry Sherwin - 1772 - 116 sider
...thereof. Whence we have the following Rule to Meafure any Circle -wbofe Diameter is given. Multip'y the Square of the Diameter by ,7854 •and the Product is nearly the Area thereof. ' If С be the Circumference of any Circle, then fince 3.1416 = с • с с с1 4 í> : i : : С :...
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A Treatise on the New Method of Land Surveying, with the Improved Plan of ...

Thomas Hornby (land surveyor.) - 1827 - 270 sider
...RULE 1st. Multiply half the Circumference by half the Diameter, and the product is the area. RULE 2. Multiply the square of the diameter by .7854 and the product is the area. EXAMPLE. Required the area of the circle whose diameter AB is 600 links. (By Prob. 7th,)...
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The Locomotive Engine Popularly Explained, and Illustrated by Lithographic ...

William Templeton - 1841 - 100 sider
...balance. THE AREA OF THE VALVE. To find the area, or number of square inches in a valve. RULE. — Multiply the square of the diameter by .7854 and the product is the area, — thus, 2.5" = 6.25 X .7854 = 4.9087 the area. THE SMOKE BOX. The shell of the smoke box...
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Elements of plane (solid) geometry (Higher geometry) and trigonometry (and ...

1845
...the circle re quired. Or thus : 31.4159 x^ =78.5398 as before. RULE II. — When the diameter only is given. Multiply the square of the diameter by .7854, and the product will be the area of the circle. For the ratio of the square described on the diameter of a circle,...
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The Decorator's assistant

...7539.8160 125.6636 = 125 ft. 8 in. nearly = arc. PROBLEM XII. To find the area of a circle. 1. When the diameter is given, multiply the square of the diameter by .7854, and the product will be the area. 2. When the circumference and diameter both are given, multiply half the circumference...
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The locomotive engine popularly explained

William Templeton (engineer.) - 1848
...balance. THE AREA OF THE VALVE. To find the area, or number of square inches in a ralve. RULE. — Multiply the square of the diameter by .7854 and the product is the area, — thus, 2.5" = 6.25 X .7854 = 4.9087 the area. THE SMOKE BOX. The shell of the smoke box...
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Mensuration and Practical Geometry: Containing Tables of Weights and ...

Charles Haynes Haswell - 1858 - 322 sider
...7, so is the circumference to the diameter. To ascertain the Area of a Circle (Fig. 22). RULE. — Multiply the square of the diameter by .7854, and the product is the area. Or, multiply the square of the circumference by .07958. Or, multiply half the circumference...
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Orton's Lightning Calculator, and Accountant's Assistant: The Shortest ...

Hoy D. Orton - 1866 - 194 sider
...the diameter by half the circumference, and the product is the area ; or, which is the same thing, multiply the square of the diameter by .7854, and the product is the area. To find the solidity of a sphere or globe. RULE. — Multiply tJie cube of the diameter by...
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A Practical Workshop Companion for Tin, Sheet Iron, and Copper Plate Workers...

Leroy J. Blinn - 1866 - 178 sider
...product is the Circumference. 2. Multiply the circumference by 81831, the product is the diameter. 3. Multiply the square of the diameter by .7854, and the product is the area. 4. Multiply the square root of the area by 1.12837, the product ia the diameter. 5. Multiply...
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Orton's Lightning Calculator and Accountant's Assistant

Hoy D. Orton - 1871 - 186 sider
...the diameter by half the< circumference, and the product is the area; ort. which is /he same thing, multiply the square of the? diameter by .7854, and the product is the area. To find the solidity of a sphere or globe. RULE. — Multiply the cube of the diameter ojf....
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