Plane and Solid GeometryGinn, 1895 - 320 sider |
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Resultat 1-5 av 34
Side vii
... INSCRIBED 66 66 66 66 3 . 4 . 5 . 6 . - - ANGLES FORMED BY CHORDS , SECANTS , AND TANGENTS AND CIRCUMSCRIBED TRIANGLES QUADRILATERALS Two CIRCLES PROBLEMS . · · 102 104 · 106 112 AND 119 123 • 126 METHODS APPENDIX TO BOOK III . BOOK IV ...
... INSCRIBED 66 66 66 66 3 . 4 . 5 . 6 . - - ANGLES FORMED BY CHORDS , SECANTS , AND TANGENTS AND CIRCUMSCRIBED TRIANGLES QUADRILATERALS Two CIRCLES PROBLEMS . · · 102 104 · 106 112 AND 119 123 • 126 METHODS APPENDIX TO BOOK III . BOOK IV ...
Side 68
... inscribe a rhombus , having one of its angles coincident with an angle of the triangle , and the other three vertices on the three sides of the triangle . 208. Draw a line parallel to a given line , so that the segment inter- cepted ...
... inscribe a rhombus , having one of its angles coincident with an angle of the triangle , and the other three vertices on the three sides of the triangle . 208. Draw a line parallel to a given line , so that the segment inter- cepted ...
Side 112
... inscribed angle , and is said to stand upon , or be subtended by , the arc which lies within the angle and is cut off by the arms . It is also called an angle inscribed in , or simply an angle in , the seg- ment whose arc is the ...
... inscribed angle , and is said to stand upon , or be subtended by , the arc which lies within the angle and is cut off by the arms . It is also called an angle inscribed in , or simply an angle in , the seg- ment whose arc is the ...
Side 113
Wooster Woodruff Beman, David Eugene Smith. Theorem 11. An inscribed angle equals half the central angle standing on the same arc . D D D Given FIG . 1 . FIG . 2 . B FIG . 3 . B AVB an inscribed angle , and AOB the central angle on the ...
Wooster Woodruff Beman, David Eugene Smith. Theorem 11. An inscribed angle equals half the central angle standing on the same arc . D D D Given FIG . 1 . FIG . 2 . B FIG . 3 . B AVB an inscribed angle , and AOB the central angle on the ...
Side 118
... segments equals the square on the diameter . 314. Given two pairs of parallel chords , AB || A'B ' , and BC || B'C ' ; prove that AC ' II A'C . Section 4. Inscribed and Circumscribed Triangles and Quadrilaterals . The 118 PLANE GEOMETRY .
... segments equals the square on the diameter . 314. Given two pairs of parallel chords , AB || A'B ' , and BC || B'C ' ; prove that AC ' II A'C . Section 4. Inscribed and Circumscribed Triangles and Quadrilaterals . The 118 PLANE GEOMETRY .
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Plane and Solid Geometry David Eugene Smith,Wooster Woodruff Beman Ingen forhåndsvisning tilgjengelig - 2016 |
Vanlige uttrykk og setninger
a₁ ABCD altitude angles are equal angles equal b₁ b₂ bisected bisectors C₁ called central angle chord circle circumcenter circumference circumscribed cone congruent construct convex COROLLARIES corresponding cylinder DEFINITIONS diagonals diameter dihedral angle divided draw drawn edges equal angles equidistant equilateral EXERCISES face angles figure of th frustum geometry given line given point greater hypotenuse inscribed interior angles intersection isosceles triangle line-segment locus lune mid-points oblique opposite sides P₁ parallel parallelepiped parallelogram perigon perimeter perpendicular plane plane geometry polyhedral angle prism Prismatoid Proof pyramid quadrilateral radii radius ratio rectangle regular regular polygon respectively rhombus right angle right-angled triangle Section segments Similarly slant height sphere spherical polygon spherical surface spherical triangle square straight angle straight line Suppose symmetric tangent tetrahedron Theorem transversal trapezoid trihedral vertex vertices
Populære avsnitt
Side 90 - The projection of a point on a line is the foot of the perpendicular from the point to the line. Thus A
Side 295 - The sum of the angles of a spherical triangle is greater than two and less than six right angles ; that is, greater than 180° and less than 540°. (gr). If A'B'C' is the polar triangle of ABC...
Side 74 - Prove analytically that the perpendiculars from the vertices of a triangle to the opposite sides meet in a point.
Side 37 - If two triangles have two sides of the one respectively equal to two sides of the other, and the contained angles supplemental, the two triangles are equal.
Side 159 - If two triangles have one angle of the one equal to one angle of the other and the sides about these equal angles proportional, the triangles are similar.
Side 225 - Theorem. If each of two intersecting planes is perpendicular to a third plane, their line of intersection is also perpendicular to that plane. Given two planes, Q, R, intersecting in OP, and each perpendicular to plane M. To prove that OP _L M.
Side 265 - A Plane Surface, or a Plane, is a surface in which if any two points are taken, the straight line which joins these points will lie wholly in the surface.
Side 94 - To construct a parallelogram equal to a given triangle and having one of its angles equal to a given angle.
Side 24 - ... 3. If two sides of a triangle are equal, the angles opposite these sides are equal ; and conversely.