Euclidian GeometryMacmillan, 1874 - 349 sider |
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Resultat 1-5 av 62
Side 2
... Hence it follows that Two straight lines cannot have a common segment . H A. B For if two straight lines ABC , ABH could have a com .. mon segment AB ; then the straight line ABC might be turned about its extremity A , towards the side ...
... Hence it follows that Two straight lines cannot have a common segment . H A. B For if two straight lines ABC , ABH could have a com .. mon segment AB ; then the straight line ABC might be turned about its extremity A , towards the side ...
Side 3
Francis Cuthbertson. Hence it follows that If two straight lines pass through the same point they will coincide entirely or cut one another . For if not , if possible let them fall otherwise as AOB , POQ having a ... Hence it follows that ...
Francis Cuthbertson. Hence it follows that If two straight lines pass through the same point they will coincide entirely or cut one another . For if not , if possible let them fall otherwise as AOB , POQ having a ... Hence it follows that ...
Side 4
... = △ DEF , Also the AABC will coincide with and is .. LABC will coincide with and is .. = DEF ; LACB is = LDFE . Hence the As ABC , DEF are equal in all respects . DEFINITION . An isosceles triangle is one which has two ( 4 )
... = △ DEF , Also the AABC will coincide with and is .. LABC will coincide with and is .. = DEF ; LACB is = LDFE . Hence the As ABC , DEF are equal in all respects . DEFINITION . An isosceles triangle is one which has two ( 4 )
Side 13
... Hence in the As ACE , BCE , ( 1.5 ) AC , CE and the included △ ACE are respectively = BC , CE and the included △ BCE ; ..as ACE , BCE are equal in all respects , and .. AE is = BE ; ( I. I ) .. AB has been bisected in E. Q. E. F. ...
... Hence in the As ACE , BCE , ( 1.5 ) AC , CE and the included △ ACE are respectively = BC , CE and the included △ BCE ; ..as ACE , BCE are equal in all respects , and .. AE is = BE ; ( I. I ) .. AB has been bisected in E. Q. E. F. ...
Side 21
... Hence in the AS AQR , FQR , L AQ , QR and 4 AQR are respectively equal to FQ , QR , and FQR ; .. LARQL FRQ . = ( I. I ) .. if ARQ were a right angle , the S ARQ , FRQ would be together two right angles , LS and . ' . ARF would be a ...
... Hence in the AS AQR , FQR , L AQ , QR and 4 AQR are respectively equal to FQ , QR , and FQR ; .. LARQL FRQ . = ( I. I ) .. if ARQ were a right angle , the S ARQ , FRQ would be together two right angles , LS and . ' . ARF would be a ...
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Algebra base Cambridge centre chord circumference cloth Conic Sections Crown 8vo Describe a circle diagonals diameter divided draw a straight ELEMENTARY TREATISE English equiangular equilateral Euclid Examples Extra fcap fcap GEOMETRY given angle given circle given point given straight line Grammar greater H Let Hence inscribed intersecting isosceles triangle Latin Let ABC line bisecting locus Mathematical meet opposite angles Owens College parallel parallelogram perimeter perpendicular plane polygon PROBLEM produced Professor proportional PROPOSITION ratio rect rectangle rectangle contained rectilineal figure regular polygon respectively revised rhombus right angles Schools Second Edition segment similar Similarly squares on AC straight line drawn straight line joining tangent THEOREM TRIGONOMETRY twice rectangle twice the squares vertex