Euclidian GeometryMacmillan, 1874 - 349 sider |
Inni boken
Resultat 1-5 av 90
Side 12
... Join AF ; then △ DAE shall be bisected by AF . Then L Join BF , CF. . in the As ABF , ACF , BA is CA , BF≈ CF , and AF is common ; = ... the As ABF , ACF are equal in all respects , ..the BAF is the CAF , and -- .. △ DAE has been ...
... Join AF ; then △ DAE shall be bisected by AF . Then L Join BF , CF. . in the As ABF , ACF , BA is CA , BF≈ CF , and AF is common ; = ... the As ABF , ACF are equal in all respects , ..the BAF is the CAF , and -- .. △ DAE has been ...
Side 13
... Join CD cutting AB in E ; Then then AB shall be bisected in E. Join AC , CB , BD , DA . in the As ACD , BCD , AC , CD , DA - are respectively = BC , CD , DB , ..As ACD , BCD are equal in all respects , .. LACD is = 4 BCD . Hence in the ...
... Join CD cutting AB in E ; Then then AB shall be bisected in E. Join AC , CB , BD , DA . in the As ACD , BCD , AC , CD , DA - are respectively = BC , CD , DB , ..As ACD , BCD are equal in all respects , .. LACD is = 4 BCD . Hence in the ...
Side 16
... Join AF . Then AF shall be to BC . Join DF , EF . ·· DA is = EA , DF = EF , and AF common to the two AS DAF , EAF , .. these as are equal in all respects ; .. ¿ DAF is = L EAF , ... AF is to BC . ( 1.5 ) ( Def . ) PROPOSITION VIII ...
... Join AF . Then AF shall be to BC . Join DF , EF . ·· DA is = EA , DF = EF , and AF common to the two AS DAF , EAF , .. these as are equal in all respects ; .. ¿ DAF is = L EAF , ... AF is to BC . ( 1.5 ) ( Def . ) PROPOSITION VIII ...
Side 20
... Join AF , cutting BC in G. Then shall AG be 1 to BC . Join AD , AE , FD , FE . Then · . · DA , AF , FD are respectively = EA , AF , FE ; .. AS DAF , EAF are equal in all respects , Again , and ... △ DAF is = LEAF . ( I. 5 ) DA , AG and ...
... Join AF , cutting BC in G. Then shall AG be 1 to BC . Join AD , AE , FD , FE . Then · . · DA , AF , FD are respectively = EA , AF , FE ; .. AS DAF , EAF are equal in all respects , Again , and ... △ DAF is = LEAF . ( I. 5 ) DA , AG and ...
Side 21
... Join FR . Then . AQR is a right 4 , .. 4 FQR is a right . ( 1.9 ) Hence in the AS AQR , FQR , L AQ , QR and 4 AQR are respectively equal to FQ , QR , and FQR ; .. LARQL FRQ . = ( I. I ) .. if ARQ were a right angle , the S ARQ , FRQ ...
... Join FR . Then . AQR is a right 4 , .. 4 FQR is a right . ( 1.9 ) Hence in the AS AQR , FQR , L AQ , QR and 4 AQR are respectively equal to FQ , QR , and FQR ; .. LARQL FRQ . = ( I. I ) .. if ARQ were a right angle , the S ARQ , FRQ ...
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Algebra base Cambridge centre chord circumference cloth Conic Sections Crown 8vo Describe a circle diagonals diameter divided draw a straight ELEMENTARY TREATISE English equiangular equilateral Euclid Examples Extra fcap fcap GEOMETRY given angle given circle given point given straight line Grammar greater H Let Hence inscribed intersecting isosceles triangle Latin Let ABC line bisecting locus Mathematical meet opposite angles Owens College parallel parallelogram perimeter perpendicular plane polygon PROBLEM produced Professor proportional PROPOSITION ratio rect rectangle rectangle contained rectilineal figure regular polygon respectively revised rhombus right angles Schools Second Edition segment similar Similarly squares on AC straight line drawn straight line joining tangent THEOREM TRIGONOMETRY twice rectangle twice the squares vertex