Euclidian GeometryMacmillan, 1874 - 349 sider |
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Resultat 1-5 av 19
Side 142
... equiangular to a given triangle . Let it be required to inscribe in the XYZ a △ equi- angular to the a PQR . Draw a tangent SZT to the 4 XYZ : at Z in ZS make SZX = 4 PQR , L and at Z in ZT make △ TZY : = 4 QPR : join XY : then XYZ ...
... equiangular to a given triangle . Let it be required to inscribe in the XYZ a △ equi- angular to the a PQR . Draw a tangent SZT to the 4 XYZ : at Z in ZS make SZX = 4 PQR , L and at Z in ZT make △ TZY : = 4 QPR : join XY : then XYZ ...
Side 143
... equiangular to a given triangle . T Q Let it be required to describe about the DEF a A equiangular to △ PQR . Produce QR both ways to S , T. Draw any radius OD and make △ DOE = 1 PRS , and DOF LPQT . = At D , E , F draw tangents to ...
... equiangular to a given triangle . T Q Let it be required to describe about the DEF a A equiangular to △ PQR . Produce QR both ways to S , T. Draw any radius OD and make △ DOE = 1 PRS , and DOF LPQT . = At D , E , F draw tangents to ...
Side 150
... equilateral ; also the arms of the PQR will coincide with those of the QRS . . Hence PQR = L QRS = L RST , & c . ; .. the figure is equiangular ; .. PQRS is a regular figure , and it is inscribed in the given O. COROLLARY . Hence we may ...
... equilateral ; also the arms of the PQR will coincide with those of the QRS . . Hence PQR = L QRS = L RST , & c . ; .. the figure is equiangular ; .. PQRS is a regular figure , and it is inscribed in the given O. COROLLARY . Hence we may ...
Side 151
... equilateral and also equiangular , i.e. it is a regular polygon and it is circumscribed about the given circle . COROLLARY . Hence we may describe about a circle regular figures of 3 , 4 , 5 , 6 , 8 & c . sides . ( III . G. H. K. ) ...
... equilateral and also equiangular , i.e. it is a regular polygon and it is circumscribed about the given circle . COROLLARY . Hence we may describe about a circle regular figures of 3 , 4 , 5 , 6 , 8 & c . sides . ( III . G. H. K. ) ...
Side 174
... equiangular . B Ꮳ A F H Let ABC , FGH be two As , such that AB AC as FG : FH , and AB : BC as FG : GH . The As ABC , FGH shall be equiangular . From the arms of the at A , produced if necessary , cut off AQ = FG , and AK = FH ; join QK ...
... equiangular . B Ꮳ A F H Let ABC , FGH be two As , such that AB AC as FG : FH , and AB : BC as FG : GH . The As ABC , FGH shall be equiangular . From the arms of the at A , produced if necessary , cut off AQ = FG , and AK = FH ; join QK ...
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Algebra base Cambridge centre chord circumference cloth Conic Sections Crown 8vo Describe a circle diagonals diameter divided draw a straight ELEMENTARY TREATISE English equiangular equilateral Euclid Examples Extra fcap fcap GEOMETRY given angle given circle given point given straight line Grammar greater H Let Hence inscribed intersecting isosceles triangle Latin Let ABC line bisecting locus Mathematical meet opposite angles Owens College parallel parallelogram perimeter perpendicular plane polygon PROBLEM produced Professor proportional PROPOSITION ratio rect rectangle rectangle contained rectilineal figure regular polygon respectively revised rhombus right angles Schools Second Edition segment similar Similarly squares on AC straight line drawn straight line joining tangent THEOREM TRIGONOMETRY twice rectangle twice the squares vertex