Euclidian GeometryMacmillan, 1874 - 349 sider |
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Resultat 1-5 av 28
Side vii
... Third Book a section has been added on the equal subdivision of the circumference of a circle , thus preparing the way for a more general consider- ation of the subject of regular polygons . In the Fourth Book the areas and perimeters ...
... Third Book a section has been added on the equal subdivision of the circumference of a circle , thus preparing the way for a more general consider- ation of the subject of regular polygons . In the Fourth Book the areas and perimeters ...
Side 26
... third . Let ABC be a △ . Then shall any two of its sides , as AB , AC , be together > BC . B Produce BA to K , making AK = AC , and join KC . Then .. AK is AC ; .. LACK is = L AKC ; ( 1. 2 ) but = BCK is > △ ACK ; .. BCK is L AKC ...
... third . Let ABC be a △ . Then shall any two of its sides , as AB , AC , be together > BC . B Produce BA to K , making AK = AC , and join KC . Then .. AK is AC ; .. LACK is = L AKC ; ( 1. 2 ) but = BCK is > △ ACK ; .. BCK is L AKC ...
Side 30
... third . Α . B C- L H E F IM Let A , B , C be the three given straight lines , any two of them being together greater than the third . It is required to describe a △ having its sides equal to A , B , C respectively . Take a straight ...
... third . Α . B C- L H E F IM Let A , B , C be the three given straight lines , any two of them being together greater than the third . It is required to describe a △ having its sides equal to A , B , C respectively . Take a straight ...
Side 127
... third of two right 4 s ; .. LS PCR , QCR are each = two thirds of two rights , and PCQ = two thirds of two rights ; .. 4S PCR , QCR , PCQ are = one another ; .. the arcs PR , QR , PQ are = one another . COR . Hence we may divide the ...
... third of two right 4 s ; .. LS PCR , QCR are each = two thirds of two rights , and PCQ = two thirds of two rights ; .. 4S PCR , QCR , PCQ are = one another ; .. the arcs PR , QR , PQ are = one another . COR . Hence we may divide the ...
Side 128
... third of the Oce , and GH = one - fifth of the Oce , bisect the arc HN in K. Then the Oce may be divided into fifteen parts each = HK . For of such parts , as the Oce contains fifteen , GN contains five , and GH contains three . .. HN ...
... third of the Oce , and GH = one - fifth of the Oce , bisect the arc HN in K. Then the Oce may be divided into fifteen parts each = HK . For of such parts , as the Oce contains fifteen , GN contains five , and GH contains three . .. HN ...
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Algebra base Cambridge centre chord circumference cloth Conic Sections Crown 8vo Describe a circle diagonals diameter divided draw a straight ELEMENTARY TREATISE English equiangular equilateral Euclid Examples Extra fcap fcap GEOMETRY given angle given circle given point given straight line Grammar greater H Let Hence inscribed intersecting isosceles triangle Latin Let ABC line bisecting locus Mathematical meet opposite angles Owens College parallel parallelogram perimeter perpendicular plane polygon PROBLEM produced Professor proportional PROPOSITION ratio rect rectangle rectangle contained rectilineal figure regular polygon respectively revised rhombus right angles Schools Second Edition segment similar Similarly squares on AC straight line drawn straight line joining tangent THEOREM TRIGONOMETRY twice rectangle twice the squares vertex