A Supplement to the Elements of EuclidG. and W. B. Whittaker, 1819 - 410 sider |
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Side 4
... . By the help of this problem , it is manifest that a circle may be described , which shall have its centre in a given straight line , and which shall pass through two given points without that line A SUPPLEMENT TO THE.
... . By the help of this problem , it is manifest that a circle may be described , which shall have its centre in a given straight line , and which shall pass through two given points without that line A SUPPLEMENT TO THE.
Side 18
... manifest , therefore , that DAB is the triangle which was to be constructed . PROP . XVI . 24. THEOREM . If two right - angled triangles have the three angles of the one equal to the three angles of the other , each to each , and if a ...
... manifest , therefore , that DAB is the triangle which was to be constructed . PROP . XVI . 24. THEOREM . If two right - angled triangles have the three angles of the one equal to the three angles of the other , each to each , and if a ...
Side 20
... manifest that it has the same number of sides as the figure ABCDEF . PROP . XVIII . 26. THEOREM . If two opposite sides of a quadri- lateral figure be equal to one another , and the two remaining sides be also equal to one another , the ...
... manifest that it has the same number of sides as the figure ABCDEF . PROP . XVIII . 26. THEOREM . If two opposite sides of a quadri- lateral figure be equal to one another , and the two remaining sides be also equal to one another , the ...
Side 22
... manifest from the construction , that AD = BC , and AB = DC : ... ( S. 16. 1. ) BC is parallel to AD . 28. COR . 2. A rhombus is a parallelogram . PROP . XIX . 29. THEOREM . Every parallelogram which has one angle a right angle , has ...
... manifest from the construction , that AD = BC , and AB = DC : ... ( S. 16. 1. ) BC is parallel to AD . 28. COR . 2. A rhombus is a parallelogram . PROP . XIX . 29. THEOREM . Every parallelogram which has one angle a right angle , has ...
Side 30
... manifest that the re- maining angle , or angles , of the one figure , must be equal to the remaining angle , or angles of the other . PROP . XXVII . 37. THEOREM . The angle at the base of an isos- celes triangle is equal to , or is less ...
... manifest that the re- maining angle , or angles , of the one figure , must be equal to the remaining angle , or angles of the other . PROP . XXVII . 37. THEOREM . The angle at the base of an isos- celes triangle is equal to , or is less ...
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Vanlige uttrykk og setninger
base BC bisect centre chord circle ABC circle described circumference constr decagon describe a circle describe the circle diameter distance divided double draw a straight draw E equi equiangular equilateral and equiangular F draw find a point finite straight line given circle given finite straight given point given ratio given square given straight line half hypotenuse inscribed isosceles less Let AB Let ABC lines be drawn magnitudes manifest manner meet the circumference number of equal number of sides parallel to BC parallelogram pass perimeter polygon PROBLEM produced PROP rectangle contained rectilineal figure remaining sides required to describe required to draw rhombus right angles segment semi-diameter straight line joining subtend tangent THEOREM three given touch the circle trapezium vertex
Populære avsnitt
Side 310 - If two triangles have one angle of the one equal to one angle of the other and the sides about these equal angles proportional, the triangles are similar.
Side 198 - If a straight line be bisected, and produced to any point ; the rectangle contained by the whole line thus produced, and the part of it produced, together with the square...
Side 366 - If from the vertical angle of a triangle a straight line be drawn perpendicular to the base, the rectangle contained by the sides of the triangle is equal to the rectangle contained by the perpendicular and the diameter of the circle described about the...
Side 92 - If there be two straight lines, one of which is divided into any number of parts, the rectangle contained by the two straight lines is equal to the rectangles contained by the undivided line, and the several parts of the divided line.
Side 284 - And if the first have a greater ratio to the second, than the third has to the fourth, but the third the same ratio to the fourth, which the fifth has to the sixth...
Side 349 - Divide a straight line into two parts such that the rectangle contained by the whole line and one of the parts shall be equal to the square on the other part.
Side 288 - Convertendo, by conversion ; when there are four proportionals, and it is inferred, that the first is to its excess above the second, as the third to its excess above the fourth.
Side 296 - ... line and the extremities of the base have the same ratio which the other sides of the triangle have to one...
Side 367 - Wherefore, in equal circles &c. QED PROPOSITION B. THEOREM If the vertical angle of a triangle be bisected by a straight line which likewise cuts the base, the rectangle contained by the sides of the triangle is equal to the rectangle contained by the segments of the base, together with the square on the straight line which bisects the angle.
Side 104 - In every triangle, the square of the side subtending any of the acute angles is less than the squares of the sides containing that angle by twice the rectangle contained by either of these sides, and the straight line intercepted between the perpendicular let fall upon it from the opposite angle, and the acute angle. Let ABC be any triangle, and the angle at B one of its acute angles, and upon BC, one of the sides containing it, let fall the perpendicular...