 Add into one sum 39 times the square of the bung diameter, 25 times the square of the head diameter, and 26 times the product of the two diameters : then multiply the sum by the length, and the product again by — —for wine gallons, or by- — —...  A Treatise on Mensuration for the Use of Schools - Side 225av Commissioners of National Education in Ireland - 1837 - 262 siderUten tilgangsbegrensning - Om denne boken
 | 1801 - 658 sider
.... b . ^ 13'poio wine gal. PROBLEM VI. 'To find the content ff any cask from three dimensions only. RULE. Add into one sum 39 times the square of the...then multiply the sum by the length, and the product by '" ° ° ;.4 for ale gallons, or by 12-°5iS, or '00003™' f°r w'ne gallons. EXAMPLES. EXAMPLES.... | |
 | Samuel Webber - 1808 - 520 sider
...ale gal. "1 13.9010 wine gal. PROBLEM VI. Tofnd the content of any cask from threc dimensions only. RULE.* Add into one sum 39 times the square of the...diameter, 25 times the square of the head diameter, and 26 * DEMONSTRATION. In this Rule it is supposed, that the sides or edges of each stave of a cask f jr... | |
 | John Mason Good - 1813 - 714 sider
...accurate, as having been often verified and proved by filling the casks with a $rue gallon measure. General Rule. Add into one sum, 39 times the square of the bung diameter, 2u times the square of the head diameter, and S(J times the product of those diameters ; multiply the... | |
 | Anthony Nesbit, W. Little - 1822 - 916 sider
...jiii'l Ike contents of casks in general, from the head diameter, bung diameter, and length. RULE I. Add into one sum, 39 times the square of the bung...of the head diameter, and 26 times the product of those diameters ; multiply this sum by the length of the cask, and the product by .00034 ; then divide... | |
 | Anthony Nesbit - 1824 - 476 sider
...gallons. Kate. The content found by the true Rule, page 338, is 40.7071 gallon!. GENERAL RULES. RULE I. Add into one sum, 39 times the square of the bung...of the head diameter, and 26 times the product of those diameters ; multiply the sum by the length of the cask, and the product by .00034 ; then this... | |
 | Peter Nicholson - 1825 - 1046 sider
...gallons, \ 13*9010 wine gallons. Prob. If. To find the content of any cask from three dimensions only. Add into one sum, 39 times the square of the bung...multiply the sum by the length, and the product again by for wine gallons, or by — or 'OOOOS-rV У • for ale gallons. Ex. 1 . Required the content of a... | |
 | John Bonnycastle - 1829 - 256 sider
...Sg { 13.9010 wine gallons. PROBLEM XVII. To find the content of any cask from three dimensions only. Add into one sum 39 times the square of the bung diameter,...multiply the sum by the length, and the product again by — —for wine gallons, or by- — — — or .00003TV, for ale ' ' 11 GAUGING. EXAMPLES. 1 . Required... | |
 | Edinburgh encyclopaedia - 1830 - 856 sider
...The content of any cask whatever may also be nearly found, in wine or ale gallons, by the following general rule: RULE. Add into one sum 39 times the...the head diameter, and 26 times the product of the diameters. Multiply the sum by the length, and the product by .00034 ; then the last product, divided... | |
 | Tobias Ostrander - 1833 - 172 sider
...any cask, having three dimensions only given. Rule—To 39 times the square of the bung diameter, add 25 times the square of the head diameter, and 26 times the product of those two diameters ; then multiply the sum by the length, and that product by ,00034, and divide the... | |
 | Ireland commissioners of nat. educ - 1834 - 370 sider
...-000236 = 89-41668 imperial gallons. PROBLEM XVIII. Tbßnd ilie content of any cask by Doctor Huttons general rule. RULE. Add into one sum, 39 times the...multiply the sum by the length, and the product again by -00031$ for the content in gallons. 1. What is the content of a cask, whose length is 40 inches, and... | |
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