Elementary Applied Mechanics: Being the Simpler and More Practical Cases of Stress and Strain Wrought Out Individually from First Principles by Means of Elementary Mathematics, Volum 2Macmillan and Company, 1883 |
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Side 46
... , which he calls the numerical co - efficient of the maximum bending moment expressed in terms of the load and span . The value of m depends upon the manner of loading and of support . In the case we 46 APPLIED MECHANICS .
... , which he calls the numerical co - efficient of the maximum bending moment expressed in terms of the load and span . The value of m depends upon the manner of loading and of support . In the case we 46 APPLIED MECHANICS .
Side 214
... numerical co- efficient assumes values other than , as will be proved hereafter . Rankine uses n for the value of this constant , which he calls the numerical coefficient of the moment of resistance to bending of any cross section ; and ...
... numerical co- efficient assumes values other than , as will be proved hereafter . Rankine uses n for the value of this constant , which he calls the numerical coefficient of the moment of resistance to bending of any cross section ; and ...
Side 295
... numerical coefficient for the deflection . In this case , the numerical coefficients are— m " = { } ; n ′′ = } . n " Observe that f is the working or proof strength of the material , according as you may want the working or proof values ...
... numerical coefficient for the deflection . In this case , the numerical coefficients are— m " = { } ; n ′′ = } . n " Observe that f is the working or proof strength of the material , according as you may want the working or proof values ...
Side 296
... numerical co - efficients are m " = } ; n " = 5 12 . Cantilever of uniform section , load at end . From fig . 23— M M 0 = W ( c − x ) ÷ WC = ( 1 − 2 ) - exactly as in the case of a beam loaded at the centre ; and the numerical co ...
... numerical co - efficients are m " = } ; n " = 5 12 . Cantilever of uniform section , load at end . From fig . 23— M M 0 = W ( c − x ) ÷ WC = ( 1 − 2 ) - exactly as in the case of a beam loaded at the centre ; and the numerical co ...
Side 297
... numerical co - efficients are m " = } ; n ′′ = 1 . n " Beam of uniform section , bending moment constant . — If a beam be symmetrically placed on , and extend beyond its two points of support ; and if the two projecting parts be loaded ...
... numerical co - efficients are m " = } ; n ′′ = 1 . n " Beam of uniform section , bending moment constant . — If a beam be symmetrically placed on , and extend beyond its two points of support ; and if the two projecting parts be loaded ...
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Elementary applied mechanics, by T. Alexander (and A.W. Thomson). Thomas Alexander (civil engineer.) Uten tilgangsbegrensning - 1883 |
Vanlige uttrykk og setninger
abscissa advancing load apex beam bending moment diagram bh³ calculate the bending cantilever centre of gravity centre of span chord College common interval construct cross section Crown 8vo curved edge passes dead load distance draw a vertical drawn Edition end of span equal example fcap feet span field Find the maximum fixed end fixed loads ft.-tons gives the maximum graphical solution greater greatest hence horizontal inch intersection left end leverage locus M₁ maxima bending moments maximum bending maximum bending moment modulus moment of inertia negative neutral axis ordinate parabola parabolic segment parallel plane polygon portion position rectangle right end rolling load scale for verticals shearing force shearing stress shown in fig side slope stress Suppose tangent total load transit triangle U+2R uniform load uniformly W₁ W₂ weights wheel whole load whole span
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