The Elements of EuclidJohnson and Warner, 1811 - 518 sider |
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Side 15
... point C , in which the circles cut one the circles another , draw the straight lines b CA , CB to the points A , B ; ABC shall be an equilateral triangle . D C Book I. a 3. Postu- late . A B E ... f 3. Ax . Because the point B OF EUCLID . 13.
... point C , in which the circles cut one the circles another , draw the straight lines b CA , CB to the points A , B ; ABC shall be an equilateral triangle . D C Book I. a 3. Postu- late . A B E ... f 3. Ax . Because the point B OF EUCLID . 13.
Side 16
Euclid Robert Simson. Book I. f 3. Ax . Because the point B is the centre of the circle CGH , BC is equal e to BG ; and because D is the centre of the circle GKL , e 15. Def . DL is equal to DG , and DA , DB , parts of them , are equal ...
Euclid Robert Simson. Book I. f 3. Ax . Because the point B is the centre of the circle CGH , BC is equal e to BG ; and because D is the centre of the circle GKL , e 15. Def . DL is equal to DG , and DA , DB , parts of them , are equal ...
Side 17
... point B shall coincide with the point E , because AB is equal to DE ; and AB coinciding with DE , AC shall coincide with DF , be- cause the angle BAC is equal to the angle EDF ; wherefore also the point C shall coincide with the point F ...
... point B shall coincide with the point E , because AB is equal to DE ; and AB coinciding with DE , AC shall coincide with DF , be- cause the angle BAC is equal to the angle EDF ; wherefore also the point C shall coincide with the point F ...
Side 18
... point F , and from AE the greater , cut off AG equal to AF , the less , and join FC , GB . a Because AF is equal to AG , and AB to AC , the two sides FA , AC are equal to the two GA , AB , each to each ; and they contain the angle FAG ...
... point F , and from AE the greater , cut off AG equal to AF , the less , and join FC , GB . a Because AF is equal to AG , and AB to AC , the two sides FA , AC are equal to the two GA , AB , each to each ; and they contain the angle FAG ...
Side 20
... F ; there E fore , because AC is equal to AD in the triangle ACD , the angles ECD , FDC upon the other side of the ... point B be on E , and the straight line BC upon EF ; the point C shall also coincide with the point F. Because BC is ...
... F ; there E fore , because AC is equal to AD in the triangle ACD , the angles ECD , FDC upon the other side of the ... point B be on E , and the straight line BC upon EF ; the point C shall also coincide with the point F. Because BC is ...
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The Elements of Euclid: The Errors, by which Theon, Or Others, Have Long Ago ... Robert Simson Uten tilgangsbegrensning - 1806 |
Vanlige uttrykk og setninger
altitude angle ABC angle BAC base BC BC is equal BC is given bisected Book XI centre circle ABCD circumference cone cylinder demonstrated described diameter draw drawn equal angles equiangular equimultiples Euclid excess fore given angle given in magnitude given in position given in species given magnitude given ratio given straight line gnomon greater join less Let ABC meet multiple parallel parallelogram parallelogram AC perpendicular point F polygon prism proportionals proposition pyramid Q. E. D. PROP radius ratio of AE rectangle CB rectangle contained rectilineal figure remaining angle right angles segment sides BA similar solid angle solid parallelopiped square of AC straight line AB straight line BC tangent THEOR third triangle ABC triplicate ratio vertex wherefore