The Elements of EuclidJohnson and Warner, 1811 - 518 sider |
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Side 13
... produced ever so far both ways , do not meet . Book I. POSTULATES . I : Let it be granted that a straight line may be drawn from any one point to any other point . II . That a terminated straight line may be produced to any length in a ...
... produced ever so far both ways , do not meet . Book I. POSTULATES . I : Let it be granted that a straight line may be drawn from any one point to any other point . II . That a terminated straight line may be produced to any length in a ...
Side 14
... produced , shall at length meet upon that side on which are " the angles which are less than two right angles . See the " notes on prop . 29. of Book I. " PROPOSITION I. PROBLEM . TO describe an equilateral triangle upon 14 THE ELEMENTS.
... produced , shall at length meet upon that side on which are " the angles which are less than two right angles . See the " notes on prop . 29. of Book I. " PROPOSITION I. PROBLEM . TO describe an equilateral triangle upon 14 THE ELEMENTS.
Side 15
... produce the straight lines DA , DB , to E and F ; from the centre B , at the dis- tance BC , described the circle CGH , and from the centre D , at the distance DG , describe the cir- cle GKL . AL shall be equal to BC . K d 1st Axi- om ...
... produce the straight lines DA , DB , to E and F ; from the centre B , at the dis- tance BC , described the circle CGH , and from the centre D , at the distance DG , describe the cir- cle GKL . AL shall be equal to BC . K d 1st Axi- om ...
Side 18
... produced to Dand E , the angle ABC shall be equal to the angle ACB , and the angle CBD to the angle BCE . a 3. 1 . 1 . In BD take any point F , and from AE the greater , cut off AG equal to AF , the less , and join FC , GB . a Because ...
... produced to Dand E , the angle ABC shall be equal to the angle ACB , and the angle CBD to the angle BCE . a 3. 1 . 1 . In BD take any point F , and from AE the greater , cut off AG equal to AF , the less , and join FC , GB . a Because ...
Side 20
... produce AC , AD to E , F ; there E fore , because AC is equal to AD in the triangle ACD , the angles ECD , FDC upon the other side of the base CD are equal to one another , but the angle ECD is greater than the angle BCD ; wherefore the ...
... produce AC , AD to E , F ; there E fore , because AC is equal to AD in the triangle ACD , the angles ECD , FDC upon the other side of the base CD are equal to one another , but the angle ECD is greater than the angle BCD ; wherefore the ...
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The Elements of Euclid: The Errors, by which Theon, Or Others, Have Long Ago ... Robert Simson Uten tilgangsbegrensning - 1806 |
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altitude angle ABC angle BAC base BC BC is equal BC is given bisected Book XI centre circle ABCD circumference cone cylinder demonstrated described diameter draw drawn equal angles equiangular equimultiples Euclid excess fore given angle given in magnitude given in position given in species given magnitude given ratio given straight line gnomon greater join less Let ABC meet multiple parallel parallelogram parallelogram AC perpendicular point F polygon prism proportionals proposition pyramid Q. E. D. PROP radius ratio of AE rectangle CB rectangle contained rectilineal figure remaining angle right angles segment sides BA similar solid angle solid parallelopiped square of AC straight line AB straight line BC tangent THEOR third triangle ABC triplicate ratio vertex wherefore