Guide to the army - competitive examinations |
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Side 22
... inches long , construct an equilateral tri- angle , and in it inscribe a circle . 2. Construct an isosceles triangle on a base of 21 inches , the angle at the vertex being 81 ° 30 ' . 3. Construct a regular pentagon on a base of 11⁄2 inch ...
... inches long , construct an equilateral tri- angle , and in it inscribe a circle . 2. Construct an isosceles triangle on a base of 21 inches , the angle at the vertex being 81 ° 30 ' . 3. Construct a regular pentagon on a base of 11⁄2 inch ...
Side 23
... inch long .. 2. Fill the triangle with a flat wash of red , the square with a flat wash of green , and the pentagon with a flat wash of the colours to match those on your paper . grey ; 3. Make a pencil drawing in light and shade , and ...
... inch long .. 2. Fill the triangle with a flat wash of red , the square with a flat wash of green , and the pentagon with a flat wash of the colours to match those on your paper . grey ; 3. Make a pencil drawing in light and shade , and ...
Side 35
... inches . 9. Investigate Maclaurin's theorem , and by means of it expand -1 tan Ꮖ as far as the term involving 3 . Afternoon Paper . 1. Find the value of 334375 of 20 shillings , of 3275 of a day , and of 4765625 of a mile . 18 of a 2 ...
... inches . 9. Investigate Maclaurin's theorem , and by means of it expand -1 tan Ꮖ as far as the term involving 3 . Afternoon Paper . 1. Find the value of 334375 of 20 shillings , of 3275 of a day , and of 4765625 of a mile . 18 of a 2 ...
Side 36
... inches long , making an angle of 30 ° with the direction of the rod , where and how must the single force act for equilibrium ? Find also the pressure on the rod in a direction perpendicular to it when the forces 7 and 5 act as above ...
... inches long , making an angle of 30 ° with the direction of the rod , where and how must the single force act for equilibrium ? Find also the pressure on the rod in a direction perpendicular to it when the forces 7 and 5 act as above ...
Side 37
... inches of copper must be fused with 12 cubic inches of gold , so that the specific gravity of the compound shall be 18.45 ? 10. When a body floats in a liquid , prove that the weight of the body is equal to the weight of the liquid ...
... inches of copper must be fused with 12 cubic inches of gold , so that the specific gravity of the compound shall be 18.45 ? 10. When a body floats in a liquid , prove that the weight of the body is equal to the weight of the liquid ...
Andre utgaver - Vis alle
Guide to the Army Competitive Examinations ... Alexander H. Hutchinson (Captain.) Uten tilgangsbegrensning - 1861 |
Guide to the Army Competitive Examinations Captain Alexander H. Hutchinson Ingen forhåndsvisning tilgjengelig - 2019 |
Guide to the Army - Competitive Examinations Alexander Hadden Hutchinson Ingen forhåndsvisning tilgjengelig - 2013 |
Vanlige uttrykk og setninger
Admiralty admission Afternoon Paper allotted appointed Army Artillery ATLAS ATLASES Australia Books Britain British Candidate Cape CAPE COLONY certificate COLONY coloured and mounted containing Council of Military Describe direct Commission ditto Drawing EDWARD STANFORD England and Wales English Language Europe EXAMINATION PAPERS Explain feet final Examination Find folded in cover French Gentleman Gentlemen Cadets Geography Geological Map Geological Survey German Grammatical Questions Greek Hindustani History inches India Mathematics miles mineral Modern Morning Paper mounted on cloth names Navy number of marks obtained Ordnance Maps ORDNANCE SURVEY parent or guardian Price Queen's Cadets R. I. MURCHISON Railways Regiments Regulations right angle Royal Artillery Royal Engineers Royal Marines Royal Military Academy Royal Military College Royal Naval College scale sheets side sons of Officers South specific gravity Stanford's subjects tion triangle varnished verbs Woolwich Write a short Zealand δὲ ἐς καὶ μὲν οἱ τε τῇ τὸ τοῦ τῶν مين
Populære avsnitt
Side 39 - Near yonder copse, where once the garden smiled, And still where many a garden -flower grows wild; There, where a few torn shrubs the place disclose, The village preacher's modest mansion rose. A man he was to all the country dear, And passing rich with forty pounds a year...
Side 72 - Nutrita faustis sub penetralibus Posset, quid Augusti paternus In pueros animus Nerones. Fortes creantur fortibus et bonis ; Est in juvencis, est in equis patrum Virtus...
Side 70 - In any right-angled triangle, the square which is described upon the side subtending the right angle, is equal to the squares described upon the sides which contain the right angle.
Side 24 - N'a rien d'humain que l'apparence ; Et d'ailleurs, il n'est pas si facile qu'on pense D'être fort honnête homme , et de jouer gros jeu.
Side 43 - Fortunatus et ille, deos qui novit agrestes, Panaque Silvanumque senem Nymphasque sorores. Ilium non populi fasces, non purpura regum Flexit et infidos agitans discordia fratres, Aut coniurato descendens Dacus ab Histro, Non res Romanae perituraque regna : neque ille Aut doluit miserans inopem aut invidit habenti.
Side 27 - He bade them follow him, and rode forward. But it seemed to be decreed that, on that day, the Lowland Scotch should in both armies appear to disadvantage. The horse hesitated. Dundee turned round, stood up in his stirrups, and, waving his hat, invited them to come on. As he lifted his arm his cuirass rose, and exposed the lower part of his left side. A musket ball struck him : his horse sprang forward and plunged into a cloud of smoke and dust which hid from both armies the fall of the victorious...
Side 69 - If one side of a triangle be produced, the exterior angle is greater than either of the interior, and opposite angles.
Side 27 - At the beginning of the action he had taken his place in front of his little band of cavalry. He bade them follow him, and rode forward. But it seemed to be decreed that, on that day, the Lowland Scotch should in both armies appear to disadvantage. The horse hesitated. Dundee turned round, and stood up in his stirrups, and, waving his hat, invited them to come on.
Side 87 - BAC is cut off from the given circle ABC containing an angle equal to the given angle D : Which was to be done. PROP. XXXV. THEOR. If two straight lines within a circle cut one another, the rectangle contained by the segments of one of them is equal to the rectangle contained by the segments of the other.
Side 89 - Infandum, Regina, jubes renovare dolorem, Trojanas ut opes et lamentabile regnum Eruerint Danai ; quaeque ipse miserrima vidi, 5 Et quorum pars magna fui.