 | John Playfair - 1829 - 210 sider
...C (figure, Prop. C), in the circumference of a circle a perpendicular CE be drawn to a diameter AE, the rectangle contained by the segments of the diameter is equal to the square of the perpendicular. Produce C.'E to the circumference at D, then CE = ED (3. 3), and AE .... | |
 | Charles Reiner - 1837 - 254 sider
...words. P.—If, from a point in the circumference of a circle, a perpendicular be drawn to the diameter, the rectangle contained by the segments of the diameter is equal to the square of the perpendicular. SUBSTANCE OF SECTION I. 1. A circle has only one centre. 2. A diameter... | |
 | Euclides - 1840 - 192 sider
...of the diameter. 89. If from any point in the diameter a perpendicular be drawn meeting any chord, or chord produced, the rectangle contained by the...perpendicular meets the chord within or without the circle. APPENDIX (E). FIFTH AND SIXTH BOOKS. X. EUCLID defines Ratio to be the relation of two magnitudes of... | |
 | Horatio Nelson Robinson - 1860 - 470 sider
...CE x ED. Hence the theorem. Cor. When one chord is a diameter, and the other at right angles to it, the rectangle contained by the segments of the diameter is equal to the square of one half the other chord ; or one half of the bisected chord is a mean proportional be~ tween... | |
 | Horatio Nelson Robinson - 1868 - 276 sider
...CE x ED. Hence the theorem. Cor. When one chord is a diameter, and the other at rignt angles to it, the rectangle contained, by the segments of the diameter is equal to the square of one half the other chord ; or one half of the bisected chord is a mean proportional between... | |
 | 1901 - 488 sider
...diameter of a circle and a chord which does not pass through the centre intersect obliquely ; prove that the rectangle contained by the segments of the diameter is equal to the rectangle contained by the segments of the chord. 6. Describe a square equal to a given equilateral... | |
 | Great Britain. Parliament. House of Commons - 1878 - 634 sider
...and BC. 3. If a diameter of a circle cut a chord of the circle but not at right angles, prove that the rectangle contained by the segments of the diameter is equal to the rectangle contained by the segments of the chord. AD nnd BC are chords of a circle cutting at right... | |
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If from any point in the diameter a perpendicular be drawn meeting any chord, or chord produced, the rectangle contained by the segments of the diameter, is equal to the sum or difference of the square of the perpendicular, and the rectangle contained... 