Euclidian Geometry |
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Resultat 1-5 av 61
Side 2
Hence it follows that Two straight lines cannot have a common segment . . H For
if two straight lines ABC , ABH could have a common segment AB ; then the
straight line ABC might be turned about its extremity A , towards the side on
which BH ...
Hence it follows that Two straight lines cannot have a common segment . . H For
if two straight lines ABC , ABH could have a common segment AB ; then the
straight line ABC might be turned about its extremity A , towards the side on
which BH ...
Side 3
Hence it follows that If two straight lines pass through the same point they will
coincide entirely or cut one another . For if not , if possible let them fall otherwise
as AOB , POQ having a common point 0 , P Then AOB might be turned about one
...
Hence it follows that If two straight lines pass through the same point they will
coincide entirely or cut one another . For if not , if possible let them fall otherwise
as AOB , POQ having a common point 0 , P Then AOB might be turned about one
...
Side 4
Hence the as ABC , DEF are equal in all respects . DEFINITION . An isosceles
triangle is one which has two ( 4 )
Hence the as ABC , DEF are equal in all respects . DEFINITION . An isosceles
triangle is one which has two ( 4 )
Side 13
AS ACD , BCD are equal in all respects , and . . ACD is = BCD . ( 1 . 5 ) Hence in
the As ACE , BCE , AC , CE and the included 2 ACE are respectively = BC , CE
and the included - BCE ; . . AS ACE , BCE are equal in all respects , and .
AS ACD , BCD are equal in all respects , and . . ACD is = BCD . ( 1 . 5 ) Hence in
the As ACE , BCE , AC , CE and the included 2 ACE are respectively = BC , CE
and the included - BCE ; . . AS ACE , BCE are equal in all respects , and .
Side 21
9 ) Hence in the as AQR , FQR , AQ , QR and L AQR are respectively equal to FQ
, QR , and – FOR ; . LARQ = FRQ . ( 1 . I ) . . if ARQ were a right angle , the 2 s
ARQ , FRQ would be together = two right angles , and . . . ARF would be a
straight ...
9 ) Hence in the as AQR , FQR , AQ , QR and L AQR are respectively equal to FQ
, QR , and – FOR ; . LARQ = FRQ . ( 1 . I ) . . if ARQ were a right angle , the 2 s
ARQ , FRQ would be together = two right angles , and . . . ARF would be a
straight ...
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base bisect Cambridge centre chapter chord circle circumference cloth College common complete construction contained Crown 8vo DEFINITION describe diameter difference divided double draw drawn Edition elementary English equal equiangular Examination Examples extremities fall fcap figure former four GEOMETRY given point given straight line Grammar greater Hence illustrations impossible inscribed introduction Join language Latin less magnitudes Master Mathematical meet method Notes opposite parallel parallelogram pass perimeter perpendicular plane polygon possible present principles PROBLEM produced Professor proportional PROPOSITION prove ratio rect rectangle render respectively revised right angles Schools segment selected sides similar Similarly square taken tangent THEOREM third touch TREATISE triangle twice University volume whole
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Bibliografisk informasjon
| Tittel | Euclidian Geometry |
| Forfatter | Francis Cuthbertson |
| Utgiver | Macmillan, 1874 |
| Original fra | Oxford University |
| Digitalisert | 8. sep 2006 |
| Lengde | 349 sider |
| Eksporter sitat | BiBTeX EndNote RefMan |