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Side vii
At the latter part of the Third Book a section has been added on the equal
subdivision of the circumference of a circle , thus preparing the way for a more
general consideration of the subject of regular polygons . In the Fourth Book the
areas ...
At the latter part of the Third Book a section has been added on the equal
subdivision of the circumference of a circle , thus preparing the way for a more
general consideration of the subject of regular polygons . In the Fourth Book the
areas ...
Side 26
Any two sides of a triangle are together greater than the third . Let ABC be a 4 .
Then shall any two of its sides , as AB , AC , be . together > BC . K Produce BA to
K , making AK = AC , and join KC . Then : : : AK is = AC ; . ' . LACK is = 1 AKC ; ( 1
.
Any two sides of a triangle are together greater than the third . Let ABC be a 4 .
Then shall any two of its sides , as AB , AC , be . together > BC . K Produce BA to
K , making AK = AC , and join KC . Then : : : AK is = AC ; . ' . LACK is = 1 AKC ; ( 1
.
Side 30
PROBLEM D . Describe a triangle having its sides equal to three given straight
lines , any two of which are together greater than the third . A . LE a . HTMK Let A
, B , C be the three given straight lines , any two of them being together greater ...
PROBLEM D . Describe a triangle having its sides equal to three given straight
lines , any two of which are together greater than the third . A . LE a . HTMK Let A
, B , C be the three given straight lines , any two of them being together greater ...
Side 127
Then ACP , ACQ are equilateral as ; . . each of the 2s ACP , ACQ is = a third of
two right < s ; . Ls PCR , QCR are each = two thirds of two right as , and 2 PCQ =
two thirds of two right 2S ; is zs PCR , QCR , PCQ are = one another ; is the arcs
PR ...
Then ACP , ACQ are equilateral as ; . . each of the 2s ACP , ACQ is = a third of
two right < s ; . Ls PCR , QCR are each = two thirds of two right as , and 2 PCQ =
two thirds of two right 2S ; is zs PCR , QCR , PCQ are = one another ; is the arcs
PR ...
Side 128
Cut off GN = one - third of the Oce , and GH = one - fifth of the Oce , bisect the arc
HN in K . Then the Oce may be divided into fifteen parts each = HK . For of such
parts , as the Oce contains fifteen , GN contains five , and GH contains three .
Cut off GN = one - third of the Oce , and GH = one - fifth of the Oce , bisect the arc
HN in K . Then the Oce may be divided into fifteen parts each = HK . For of such
parts , as the Oce contains fifteen , GN contains five , and GH contains three .
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base bisect Cambridge centre chapter chord circle circumference cloth College common complete construction contained Crown 8vo DEFINITION describe diameter difference divided double draw drawn Edition elementary English equal equiangular Examination Examples extremities fall fcap figure former four GEOMETRY given point given straight line Grammar greater Hence illustrations impossible inscribed introduction Join language Latin less magnitudes Master Mathematical meet method Notes opposite parallel parallelogram pass perimeter perpendicular plane polygon possible present principles PROBLEM produced Professor proportional PROPOSITION prove ratio rect rectangle render respectively revised right angles Schools segment selected sides similar Similarly square taken tangent THEOREM third touch TREATISE triangle twice University volume whole
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Side 157 - The first of four magnitudes is said to have the same ratio to the second, which the third has to the fourth, when any equimultiples whatsoever of the first and third being taken, and any equimultiples whatsoever of the second and fourth ; if the multiple of the first be less than that of the second, the multiple of the third is also less than that of the fourth...
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