## The Elements of Euclid: Also the Book of Euclid's Data ...cor. viz. The first six books, together with the eleventh and twelfth |

### Inni boken

Resultat 1-5 av 5

Side 24

I. For if it be not greater , it must either be equal to it , or less . but the

not equal to the angle EDF , because then the bafe BC would be equal a to EF .

but it is not , therefore the A

I. For if it be not greater , it must either be equal to it , or less . but the

**angle BAC**isnot equal to the angle EDF , because then the bafe BC would be equal a to EF .

but it is not , therefore the A

**angle BAC**is not eD qual to the angle EDF . neither ... Side 85

IN D N a circle , the

segment greater than a semicircle is less than ... And because the two

ABC ,

IN D N a circle , the

**angle**in a semicircle is a right**angle**; but the**angle**in asegment greater than a semicircle is less than ... And because the two

**angles**ABC ,

**BAC**of the triangle ABC are together less than two right**angles**, and that**BAC**is a ... Side 183

6 . the triangle ABC is equiangular to DCE . therefore the angle Book VI . ABC is

equal to the angle DCE . and the

therefore the whole angle Ac £ is equal to the two angles ABC , BAC . add the ...

6 . the triangle ABC is equiangular to DCE . therefore the angle Book VI . ABC is

equal to the angle DCE . and the

**angle BAC**was proved to be equal to ACD .therefore the whole angle Ac £ is equal to the two angles ABC , BAC . add the ...

Side 205

I F a solid angle be contained by three plane angles , See N. any two of them are

greater than the third . Let the solid angle at A be contained by the three plane

...

I F a solid angle be contained by three plane angles , See N. any two of them are

greater than the third . Let the solid angle at A be contained by the three plane

**angles BAC**, CAD , DAB . any two of them are greater than the third . If the angles...

Side 425

Dat , OPQ . because , as has been shewn , the ratio of AD to BC is the fame with

the ratio of ( HF to FL , that is , by the construction , with the ratio of ) OR to PQ ;

and the

similar ...

Dat , OPQ . because , as has been shewn , the ratio of AD to BC is the fame with

the ratio of ( HF to FL , that is , by the construction , with the ratio of ) OR to PQ ;

and the

**angle BAC**is equal to the angle POO . therefore the triangle ABC issimilar ...

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### Vanlige uttrykk og setninger

added alſo altitude angle ABC angle BAC baſe becauſe Book Book XI caſe circle circle ABCD circumference common cone cylinder Definition demonſtrated deſcribed diameter divided double draw drawn equal equal angles equiangular equimultiples exceſs fame fides firſt folid fore four fourth given angle given in poſition given in ſpecies given magnitude given ratio given ſtraight line greater Greek half join leſs likewiſe magnitude manner meet muſt oppoſite parallel parallelogram perpendicular plane priſm produced PROP proportionals Propoſition pyramid radius reaſon rectangle rectangle contained remaining right angles ſame ſecond ſegment ſhall ſhewn ſides ſimilar ſolid ſphere ſquare ſquare of AC taken THEOR theſe third thro triangle ABC wherefore whole

### Populære avsnitt

Side 157 - D ; wherefore the remaining angle at C is equal to the remaining angle at F ; Therefore the triangle ABC is equiangular to the triangle DEF. Next, let each of the angles at C, F be not less than a right angle ; the triangle ABC is also, in this case, equiangular to the triangle DEF.

Side 24 - ... be equal, each to each ; and also the third angle of the one to the third angle of the other. Let ABC, DEF be two triangles which have the angles ABC, ECA equal to the angles DEF, EFD, viz.

Side 45 - If a straight line be divided into any two parts, the rectangle contained by the whole and one of the parts, is equal to the rectangle contained by the two parts, together with the square of the aforesaid part.

Side 73 - THE straight line drawn at right angles to the diameter of a circle, from the extremity of...

Side 163 - If two triangles have one angle of the one equal to one angle of the other and the sides about these equal angles proportional, the triangles are similar.

Side 81 - ELF. Join BC, EF ; and because the circles ABC, DEF are equal, the straight lines drawn from their centres are equal: therefore the two sides BG, GC, are equal to the two EH, HF ; and the angle at G is equal to the angle at H ; therefore the base BC is equal (4.

Side 323 - Equiangular parallelograms have to one another the ratio which is compounded of the ratios of their sides.

Side 80 - EA : and because AD is equal to DC, and DE common to the triangles ADE, CDE, the two sides AD, DE are equal to the two CD, DE, each to each ; and the angle ADE is equal to the angle CDE, for each of them is a right angle ; therefore the base AE is equal (4.

Side 36 - To a given straight line to apply a parallelogram, which shall be equal to a given triangle, and have one of its angles equal to a given rectilineal angle.