The Elements of Euclid: Also the Book of Euclid's Data ...cor. viz. The first six books, together with the eleventh and twelfth |
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Resultat 1-5 av 6
Side 135
THEOR , IF F a whole magnitude be to a whole , as a magnitude Sce N. taken
from the first is to a magnitude taken from the other ; the remainder shall be to the
remainder as the whole to the whole , Let the whole AB be to the whole CD , as
AE ...
THEOR , IF F a whole magnitude be to a whole , as a magnitude Sce N. taken
from the first is to a magnitude taken from the other ; the remainder shall be to the
remainder as the whole to the whole , Let the whole AB be to the whole CD , as
AE ...
Side 136
Wherefore if the whole , & c . Q. E. D. B D COR . If the whole be to the whole , as a
magnitude taken from the first is to a magnitude taken from the other ; the
remainder likewise is to the remainder , as the magnitude taken from the first to
that ...
Wherefore if the whole , & c . Q. E. D. B D COR . If the whole be to the whole , as a
magnitude taken from the first is to a magnitude taken from the other ; the
remainder likewise is to the remainder , as the magnitude taken from the first to
that ...
Side 177
Let AF be any parallelogram applied to AK any other part of AB than the half , so
as to be deficient from the parallelogram upon the whole line AB by the
parallelogram KH similar and fimilarly situated to CE ; AD is greater than AF . First
, Let AK ...
Let AF be any parallelogram applied to AK any other part of AB than the half , so
as to be deficient from the parallelogram upon the whole line AB by the
parallelogram KH similar and fimilarly situated to CE ; AD is greater than AF . First
, Let AK ...
Side 269
... 520 5 . therefore as the pyramid AKOL to the pyramid EMSN , so is the whole
pyramid the base of which is the polygon DQATBYCV , and vertex L , to the
whole pyramid of which the base is the polygon HISEOFPGR , and vertex N.
wherefore ...
... 520 5 . therefore as the pyramid AKOL to the pyramid EMSN , so is the whole
pyramid the base of which is the polygon DQATBYCV , and vertex L , to the
whole pyramid of which the base is the polygon HISEOFPGR , and vertex N.
wherefore ...
Side 366
See N. I F the whole have to the whole a given ratio , and the parts have to the
parts given , but not the same , ratios , every one of them , whole or part , shall
have to every one a given ratio . b . Let the whole AB have a given ratio to the
whole ...
See N. I F the whole have to the whole a given ratio , and the parts have to the
parts given , but not the same , ratios , every one of them , whole or part , shall
have to every one a given ratio . b . Let the whole AB have a given ratio to the
whole ...
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added alſo altitude angle ABC angle BAC baſe becauſe Book Book XI caſe circle circle ABCD circumference common cone cylinder Definition demonſtrated deſcribed diameter divided double draw drawn equal equal angles equiangular equimultiples exceſs fame fides firſt folid fore four fourth given angle given in poſition given in ſpecies given magnitude given ratio given ſtraight line greater Greek half join leſs likewiſe magnitude manner meet muſt oppoſite parallel parallelogram perpendicular plane priſm produced PROP proportionals Propoſition pyramid radius reaſon rectangle rectangle contained remaining right angles ſame ſecond ſegment ſhall ſhewn ſides ſimilar ſolid ſphere ſquare ſquare of AC taken THEOR theſe third thro triangle ABC wherefore whole
Populære avsnitt
Side 157 - D ; wherefore the remaining angle at C is equal to the remaining angle at F ; Therefore the triangle ABC is equiangular to the triangle DEF. Next, let each of the angles at C, F be not less than a right angle ; the triangle ABC is also, in this case, equiangular to the triangle DEF.
Side 24 - ... be equal, each to each ; and also the third angle of the one to the third angle of the other. Let ABC, DEF be two triangles which have the angles ABC, ECA equal to the angles DEF, EFD, viz.
Side 45 - If a straight line be divided into any two parts, the rectangle contained by the whole and one of the parts, is equal to the rectangle contained by the two parts, together with the square of the aforesaid part.
Side 73 - THE straight line drawn at right angles to the diameter of a circle, from the extremity of...
Side 163 - If two triangles have one angle of the one equal to one angle of the other and the sides about these equal angles proportional, the triangles are similar.
Side 81 - ELF. Join BC, EF ; and because the circles ABC, DEF are equal, the straight lines drawn from their centres are equal: therefore the two sides BG, GC, are equal to the two EH, HF ; and the angle at G is equal to the angle at H ; therefore the base BC is equal (4.
Side 323 - Equiangular parallelograms have to one another the ratio which is compounded of the ratios of their sides.
Side 80 - EA : and because AD is equal to DC, and DE common to the triangles ADE, CDE, the two sides AD, DE are equal to the two CD, DE, each to each ; and the angle ADE is equal to the angle CDE, for each of them is a right angle ; therefore the base AE is equal (4.
Side 36 - To a given straight line to apply a parallelogram, which shall be equal to a given triangle, and have one of its angles equal to a given rectilineal angle.