Special Reports on Educational Subjects, Volumer 6-7

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Side 176 - Prove that parallelograms on the same base and between the same parallels are equal in area.
Side 178 - Similar triangles are to one another in the duplicate ratio of their homologous sides.
Side 374 - Rather than that gray king, whose name, a ghost, Streams like a cloud, man-shaped, from mountain peak, And cleaves to cairn and cromlech still...
Side 171 - To describe an isosceles triangle, having each of the angles at the base double of the third angle.
Side 170 - If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz.
Side 135 - THE sun descending in the west The evening star does shine, The birds are silent in their nest And I must seek for mine, The moon, like a flower In heaven's high bower, With silent delight Sits and smiles on the night...
Side 162 - If the angle of a triangle be divided into two equal angles, by a straight line which also cuts the base ; the segments of the base shall have the same ratio which the other sides of the triangle have to one another...
Side 177 - If two triangles have one angle of the one equal to one angle of the other and the sides about these equal angles proportional, the triangles are similar.
Side 165 - The areas of two triangles which have an angle of the one equal to an angle of the other are to each other as the products of the sides including the equal angles. D c A' D' Hyp. In triangles ABC and A'B'C', ZA = ZA'. To prove AABC = ABxAC. A A'B'C' A'B'xA'C' Proof. Draw the altitudes BD and B'D'.
Side 163 - UPON a given straight line to describe a segment of a circle containing an angle equal to a given rectilineal angle.

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