The College Euclid: Comprising the First Six and the Parts of the Eleventh and Twelfth Books Read at the Universities ... By A. K. Isbister1865 |
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Side 2
... called the centre of the circlé . Ө XVII . A diameter of a circle is a straight line drawn through the centre , and terminated both ways by the circum- ference . XVIII . A semicircle is the figure contained by a 2 THE ELEMENTS OF EUCLID .
... called the centre of the circlé . Ө XVII . A diameter of a circle is a straight line drawn through the centre , and terminated both ways by the circum- ference . XVIII . A semicircle is the figure contained by a 2 THE ELEMENTS OF EUCLID .
Side 6
... circle BCD ; ( post . 3 ) from the centre B , at the distance BA , describe the circle ACE ; and from the point C , in which the circles cut one another , draw the straight lines CA , CB , to the points A , B. ( post . 1. ) Then ABC ...
... circle BCD ; ( post . 3 ) from the centre B , at the distance BA , describe the circle ACE ; and from the point C , in which the circles cut one another , draw the straight lines CA , CB , to the points A , B. ( post . 1. ) Then ABC ...
Side 7
... circle CGH , ( post . 3 ) and from the centre D , at the distance DG , describe the circle GKL . Then AL shall be equal to BC . DEMONSTRATION Because the point B is the centre of the circle CGH , therefore BC is equal to BG ; ( def . 15 ) ...
... circle CGH , ( post . 3 ) and from the centre D , at the distance DG , describe the circle GKL . Then AL shall be equal to BC . DEMONSTRATION Because the point B is the centre of the circle CGH , therefore BC is equal to BG ; ( def . 15 ) ...
Side 8
... circle DEF . ( post . 3. ) Then AE shall be equal to C. DEMONSTRATION Because A is the centre of the circle DEF , therefore AE is equal to AD ; ( def . 15 ) but the straight line C is likewise equal to AD ; ( constr . ) therefore AE and ...
... circle DEF . ( post . 3. ) Then AE shall be equal to C. DEMONSTRATION Because A is the centre of the circle DEF , therefore AE is equal to AD ; ( def . 15 ) but the straight line C is likewise equal to AD ; ( constr . ) therefore AE and ...
Side 19
... circle EGF , meeting AB in F , G ; ( post . 3 ) bisect FG in H , ( 1. 10 ) and join CF , CH , CG . Then the straight line CH , drawn from the point C , is perpendicular to the given straight line AB . DEMONSTRATION Because FH is equal ...
... circle EGF , meeting AB in F , G ; ( post . 3 ) bisect FG in H , ( 1. 10 ) and join CF , CH , CG . Then the straight line CH , drawn from the point C , is perpendicular to the given straight line AB . DEMONSTRATION Because FH is equal ...
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The College Euclid: Comprising the First Six and the Parts of the Eleventh ... Euclides Uten tilgangsbegrensning - 1865 |
The College Euclid: Comprising the First Six and the Parts of the Eleventh ... Euclides Ingen forhåndsvisning tilgjengelig - 2016 |
Vanlige uttrykk og setninger
ABCD AC is equal adjacent angles angle ABC angle ACB angle BAC angle equal base BC bisect Book centre circle ABC circumference compounded constr DEMONSTRATION diameter double draw Edition English equal angles equal straight lines equal to BC equiangular equilateral and equiangular equimultiples Euclid exterior angle four magnitudes fourth French given circle given point given rectilineal angle given straight line gnomon Grammar greater ratio inscribed isosceles triangle join less Let ABC multiple opposite angles parallel parallelogram pentagon perpendicular plane polygon proportionals proposition Q. E. D. PROP rectangle contained rectilineal figure References-Prop remaining angle right angles segment similar solid angle square of AC straight line AC THEOREM third three straight lines touches the circle triangle ABC twice the rectangle wherefore
Populære avsnitt
Side 140 - If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz. either the sides adjacent to the equal...
Side xiv - The straight line drawn at right angles to the diameter of a circle, from the extremity of it, falls without the circle...
Side 310 - IF a side of any triangle be produced, the exterior angle is equal to the two interior and opposite angles ; and the three interior angles of every triangle are equal to two right angles.
Side 33 - That, if a straight line falling on two straight lines make the interior angles on the same side less than two right angles, the two straight lines, if produced indefinitely, meet on that side on which are the angles less than the two right angles.
Side vi - If a straight line be divided into any two parts, four times the rectangle contained ~by the whole line and one of the parts, together with the square on the other part, is equal to the square on the straight line which is made up of the whole and that part.
Side 310 - All the interior angles of any rectilineal figure, together with four right angles, are equal to twice as many right angles as the figure has sides.
Side xxxvii - The areas of two triangles which have an angle of the one equal to an angle of the other are to each other as the products of the sides including the equal angles. D c A' D' Hyp. In triangles ABC and A'B'C', ZA = ZA'. To prove AABC = ABxAC. A A'B'C' A'B'xA'C' Proof. Draw the altitudes BD and B'D'.
Side 69 - To divide a given straight line into two parts, so that the rectangle contained by the whole and one of the parts, shall be equal to the square of the other part.
Side 287 - If any point be taken in the diameter of a circle which is not the centre, of all the straight lines which can be drawn from it to the circumference, the greatest is that in which the centre is, and the other part of that diameter is the least...