The Elements of Euclid, Bøker 1-6;Bok 11 |
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Side 21
B and the angle AEB is equal to the angle CEF , because they are opposite
vertical angles ; [ I. 15 . therefore the triangle ... Produce BC to D. Then because
ACD is the exterior angle of the triangle ABC , it is greater than the interior
opposite ...
B and the angle AEB is equal to the angle CEF , because they are opposite
vertical angles ; [ I. 15 . therefore the triangle ... Produce BC to D. Then because
ACD is the exterior angle of the triangle ABC , it is greater than the interior
opposite ...
Side 22
The greater side of every triangle has the greater angle opposite to it . Let ABC
be a triangle , of which the side AC is greator than the side AB : the angle ABC is
also greater than the angle ACB . Because AC is greater than AB , make AD
equal ...
The greater side of every triangle has the greater angle opposite to it . Let ABC
be a triangle , of which the side AC is greator than the side AB : the angle ABC is
also greater than the angle ACB . Because AC is greater than AB , make AD
equal ...
Side 95
therefore the three angles CAB , ACB , ABC , are equal to the two angles ABC ,
ADC . But the angles CAB ... In the same manner it may be shown that the angles
BAD , BCD are together equal to two right angles . Wherefore , the opposite ...
therefore the three angles CAB , ACB , ABC , are equal to the two angles ABC ,
ADC . But the angles CAB ... In the same manner it may be shown that the angles
BAD , BCD are together equal to two right angles . Wherefore , the opposite ...
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Vanlige uttrykk og setninger
ABCD AC is equal angle ABC angle ACB angle BAC Axiom base bisected Book centre circle circle ABC circumference common Construction contained Corollary Definition demonstration described diameter divided double draw drawn edition Elements equal equal angles equiangular equilateral equimultiples Euclid exterior angle extremities fall figure four fourth given given straight line greater half Hypothesis impossible join less Let ABC magnitudes manner meet multiple namely parallel parallelogram pass perpendicular plane polygon PROBLEM produced proportionals Q.E.D. PROPOSITION ratio reason rectangle rectangle contained rectilineal figure right angles segment shewn sides similar Simson square square on AC straight line &c suppose Take taken THEOREM third triangle ABC Wherefore whole
Bibliografisk informasjon
| Tittel | The Elements of Euclid, Bøker 1-6;Bok 11 Utgave 891 av Everyman's library Utgave 891 av Everyman's library, ed. by Ernest Rhys. Science. [No. 891] Utgave 891 av Everyman's library: Science |
| Forfatter | Euclid |
| Redaktører | Isaac Todhunter, Robert Simson |
| Utgiver | J.M. Dent & Sons, Limited, 1933 |
| Original fra | University of California, Berkeley |
| Digitalisert | 5. aug 2019 |
| Lengde | 298 sider |
| Eksporter sitat | BiBTeX EndNote RefMan |