The Elements of Euclid, Bøker 1-6;Bok 11J.M. Dent & Sons, Limited, 1933 - 298 sider |
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Resultat 1-3 av 27
Side 21
Euclid Isaac Todhunter, Robert Simson. and the angle AEB is equal to the angle CEF , because they are opposite ver ... ACB Therefore the angles ACD , ACB Д B are greater than the angles ABC , ACB . But the angles ACD , ACB are together ...
Euclid Isaac Todhunter, Robert Simson. and the angle AEB is equal to the angle CEF , because they are opposite ver ... ACB Therefore the angles ACD , ACB Д B are greater than the angles ABC , ACB . But the angles ACD , ACB are together ...
Side 22
... triangle has the greater angle opposite to it . Let ABC be a triangle , of which the side AC is greator than the side AB : the angle ABC is also greater than the angle ACB . Because AC is greater than AB , make AD cqual to AB , [ I. 3 ...
... triangle has the greater angle opposite to it . Let ABC be a triangle , of which the side AC is greator than the side AB : the angle ABC is also greater than the angle ACB . Because AC is greater than AB , make AD cqual to AB , [ I. 3 ...
Side 95
Euclid Isaac Todhunter, Robert Simson. therefore the three angles CAB , ACB , ABC , are equal to the two angles ABC , ADC . But the angles CAB , ACB , ABC are together equal to two right angles ; [ I. 32 . therefore also the angles ABC ...
Euclid Isaac Todhunter, Robert Simson. therefore the three angles CAB , ACB , ABC , are equal to the two angles ABC , ADC . But the angles CAB , ACB , ABC are together equal to two right angles ; [ I. 32 . therefore also the angles ABC ...
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Vanlige uttrykk og setninger
ABCD AC is equal adjacent angles angle ABC angle ACB angle BAC angle DEF angle EDF angles equal Axiom base BC bisected centre circle ABC circumference Constr Construction Corollary Definition 15 demonstration diameter double draw equal angles equal to F equiangular equimultiples Euclid Euclid's Elements exterior angle fourth given circle given straight line gnomon greater ratio greater than F Hypothesis less Let ABC Let the straight meet multiple opposite angle parallel to BC parallelogram perpendicular polygon produced proportionals PROPOSITION 13 Q.E.D. PROPOSITION rectangle contained remaining angle right angles segment shewn sides similar and similarly Simson square described square on AC straight line &c straight line AB THEOREM tiples touches the circle triangle ABC triangle DEF twice the rectangle Wherefore