The Elements of Euclid, Bøker 1-6;Bok 11J.M. Dent & Sons, Limited, 1933 - 298 sider |
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Side 174
... base CD , so shall the triangle ABC be to the triangle ACD , and the parallelogram EC to the parallelogram CF ... base HC is of the base BC , the same multiple is the triangle AHC of the tri- angle ABC . For the same reason , whatever ...
... base CD , so shall the triangle ABC be to the triangle ACD , and the parallelogram EC to the parallelogram CF ... base HC is of the base BC , the same multiple is the triangle AHC of the tri- angle ABC . For the same reason , whatever ...
Side 175
... base HC be greater than the base CL , the triangle AHC is greater than the triangle ACL ; and if equal , equal ; and if less , less ; therefore as the base BC is to the base CD , so is the triangle ABC to the triangle ACD . [ V ...
... base HC be greater than the base CL , the triangle AHC is greater than the triangle ACL ; and if equal , equal ; and if less , less ; therefore as the base BC is to the base CD , so is the triangle ABC to the triangle ACD . [ V ...
Side 225
... base AF is equal to the base BF . For the same reason CF is equal to DF . [ I. 4 . And since it has been shown that the two sides DA , AF are equal to the two sides CB , BF , each to each , and that the base DF is equal to the base CF ...
... base AF is equal to the base BF . For the same reason CF is equal to DF . [ I. 4 . And since it has been shown that the two sides DA , AF are equal to the two sides CB , BF , each to each , and that the base DF is equal to the base CF ...
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Vanlige uttrykk og setninger
ABCD AC is equal adjacent angles angle ABC angle ACB angle BAC angle DEF angle EDF angles equal Axiom base BC bisected centre circle ABC circumference Constr Construction Corollary Definition 15 demonstration diameter double draw equal angles equal to F equiangular equimultiples Euclid Euclid's Elements exterior angle fourth given circle given straight line gnomon greater ratio greater than F Hypothesis less Let ABC Let the straight meet multiple opposite angle parallel to BC parallelogram perpendicular polygon produced proportionals PROPOSITION 13 Q.E.D. PROPOSITION rectangle contained remaining angle right angles segment shewn sides similar and similarly Simson square described square on AC straight line &c straight line AB THEOREM tiples touches the circle triangle ABC triangle DEF twice the rectangle Wherefore