The Elements of Euclid, Bøker 1-6;Bok 11 |
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Side 76
THEOREM . If in a circle two straight lines cut one another , which do not pass
through the centre , they do not bisect one another . Let ABCD be a circle , and
AC , BD two straight lines in it , which cut one another at the point E , and do not
both ...
THEOREM . If in a circle two straight lines cut one another , which do not pass
through the centre , they do not bisect one another . Let ABCD be a circle , and
AC , BD two straight lines in it , which cut one another at the point E , and do not
both ...
Side 77
points B , C : they shall not have the same centre . For , if it be possible , tet E be
their contre ; join EC , and draw any straight line EFG meeting the circumferences
at F and G. Then , because E is the centre of the circle ABC , EC is equal to EF .
points B , C : they shall not have the same centre . For , if it be possible , tet E be
their contre ; join EC , and draw any straight line EFG meeting the circumferences
at F and G. Then , because E is the centre of the circle ABC , EC is equal to EF .
Side 92
THEOREM , If a straight line touch a circle , and from the point of contact a
straight line be drawn at right angles to the touching line , the centre of the circle
shati be in that line . Let the straight line DE touch the circ ! e ABC at C , and from
C let ...
THEOREM , If a straight line touch a circle , and from the point of contact a
straight line be drawn at right angles to the touching line , the centre of the circle
shati be in that line . Let the straight line DE touch the circ ! e ABC at C , and from
C let ...
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ABCD AC is equal angle ABC angle ACB angle BAC Axiom base bisected Book centre circle circle ABC circumference common Construction contained Corollary Definition demonstration described diameter divided double draw drawn edition Elements equal equal angles equiangular equilateral equimultiples Euclid exterior angle extremities fall figure four fourth given given straight line greater half Hypothesis impossible join less Let ABC magnitudes manner meet multiple namely parallel parallelogram pass perpendicular plane polygon PROBLEM produced proportionals Q.E.D. PROPOSITION ratio reason rectangle rectangle contained rectilineal figure right angles segment shewn sides similar Simson square square on AC straight line &c suppose Take taken THEOREM third triangle ABC Wherefore whole