The Elements of Euclid, Bøker 1-6;Bok 11 |
Inni boken
Resultat 1-3 av 16
Side 24
But it has been shown that BA , AC are greater than BE , EC ; much more then
are BA , AC greater than BD , DC . Again , because the exterior angle of any
triangle is greater than the interior opposite angle , the exterior angle BDC of the
...
But it has been shown that BA , AC are greater than BE , EC ; much more then
are BA , AC greater than BD , DC . Again , because the exterior angle of any
triangle is greater than the interior opposite angle , the exterior angle BDC of the
...
Side 32
E D Let the straight line EF , which falls on the two straight lines AB , CD , make
the exterior angle EGB equal to the interior and opposite angle GHD on the same
side , or make the interior angles on the same side BGH , GHD together equal to
...
E D Let the straight line EF , which falls on the two straight lines AB , CD , make
the exterior angle EGB equal to the interior and opposite angle GHD on the same
side , or make the interior angles on the same side BGH , GHD together equal to
...
Side 35
If a side of any triangle be produced , the exterior angle is equal to the two interior
and opposite angles ; and the three interior angles of every triangle are together
equal to two right angles . Let ABC be a triangle , and let one of its sides BO be ...
If a side of any triangle be produced , the exterior angle is equal to the two interior
and opposite angles ; and the three interior angles of every triangle are together
equal to two right angles . Let ABC be a triangle , and let one of its sides BO be ...
Hva folk mener - Skriv en omtale
Vi har ikke funnet noen omtaler på noen av de vanlige stedene.
Andre utgaver - Vis alle
Vanlige uttrykk og setninger
ABCD AC is equal angle ABC angle ACB angle BAC Axiom base bisected Book centre circle circle ABC circumference common Construction contained Corollary Definition demonstration described diameter divided double draw drawn edition Elements equal equal angles equiangular equilateral equimultiples Euclid exterior angle extremities fall figure four fourth given given straight line greater half Hypothesis impossible join less Let ABC magnitudes manner meet multiple namely parallel parallelogram pass perpendicular plane polygon PROBLEM produced proportionals Q.E.D. PROPOSITION ratio reason rectangle rectangle contained rectilineal figure right angles segment shewn sides similar Simson square square on AC straight line &c suppose Take taken THEOREM third triangle ABC Wherefore whole