The Elements of Euclid, Bøker 1-6;Bok 11 |
Inni boken
Resultat 1-3 av 51
Side 31
For if not , AB and CD , being produced , will meet either towards B , D or towards
A , C. Let them be pro duced and meet towards B , D at the point G. E B of
Therefore GEF is a triangle , and its exterior angle AEF is greater than the interior
...
For if not , AB and CD , being produced , will meet either towards B , D or towards
A , C. Let them be pro duced and meet towards B , D at the point G. E B of
Therefore GEF is a triangle , and its exterior angle AEF is greater than the interior
...
Side 33
But if a straight line meet two straight lines , so as to make the two interior angles
on the same sido of it , taken together , less than two right angles , these straight
lines being continually produced , shall at length meet on that side on which are ...
But if a straight line meet two straight lines , so as to make the two interior angles
on the same sido of it , taken together , less than two right angles , these straight
lines being continually produced , shall at length meet on that side on which are ...
Side 278
3 suppose AK produced to meet the circle again ; and at the point of intersection
draw a straight line touching the circle ; this straight line with parts of NB and NC ,
will form a triangle , which will be equiangular to the triangle MLN , and ...
3 suppose AK produced to meet the circle again ; and at the point of intersection
draw a straight line touching the circle ; this straight line with parts of NB and NC ,
will form a triangle , which will be equiangular to the triangle MLN , and ...
Hva folk mener - Skriv en omtale
Vi har ikke funnet noen omtaler på noen av de vanlige stedene.
Andre utgaver - Vis alle
Vanlige uttrykk og setninger
ABCD AC is equal angle ABC angle ACB angle BAC Axiom base bisected Book centre circle circle ABC circumference common Construction contained Corollary Definition demonstration described diameter divided double draw drawn edition Elements equal equal angles equiangular equilateral equimultiples Euclid exterior angle extremities fall figure four fourth given given straight line greater half Hypothesis impossible join less Let ABC magnitudes manner meet multiple namely parallel parallelogram pass perpendicular plane polygon PROBLEM produced proportionals Q.E.D. PROPOSITION ratio reason rectangle rectangle contained rectilineal figure right angles segment shewn sides similar Simson square square on AC straight line &c suppose Take taken THEOREM third triangle ABC Wherefore whole