The Elements of Euclid, Bøker 1-6;Bok 11 |
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Side 243
Therefore all the angles at the bases of the triangles are together greater than all
the angles of the polygon . Now all the angles of the triangles are together equal
to twice as many right angles as there are triangles , that is , as there are sides ...
Therefore all the angles at the bases of the triangles are together greater than all
the angles of the polygon . Now all the angles of the triangles are together equal
to twice as many right angles as there are triangles , that is , as there are sides ...
Side 248
But the polygon AXBOCPDR is less than the circle ABCD in which it is inscribed ,
therefore the polygon EKFLGMHN is less than the space S ; [ V. 14 . but it is also
greater , as has been shewn ; which is impossible . Therefore the square on BD ...
But the polygon AXBOCPDR is less than the circle ABCD in which it is inscribed ,
therefore the polygon EKFLGMHN is less than the space S ; [ V. 14 . but it is also
greater , as has been shewn ; which is impossible . Therefore the square on BD ...
Side 279
Hence also regular polygons having as many sides as any of these numbers may
be inscribed in a circle , or described about a circle . This however does not
enable us to describe a regular polygon of any assigned number of sides ; for ...
Hence also regular polygons having as many sides as any of these numbers may
be inscribed in a circle , or described about a circle . This however does not
enable us to describe a regular polygon of any assigned number of sides ; for ...
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ABCD AC is equal angle ABC angle ACB angle BAC Axiom base bisected Book centre circle circle ABC circumference common Construction contained Corollary Definition demonstration described diameter divided double draw drawn edition Elements equal equal angles equiangular equilateral equimultiples Euclid exterior angle extremities fall figure four fourth given given straight line greater half Hypothesis impossible join less Let ABC magnitudes manner meet multiple namely parallel parallelogram pass perpendicular plane polygon PROBLEM produced proportionals Q.E.D. PROPOSITION ratio reason rectangle rectangle contained rectilineal figure right angles segment shewn sides similar Simson square square on AC straight line &c suppose Take taken THEOREM third triangle ABC Wherefore whole