Elements of Geometry and Trigonometry from the Works of A.M. Legendre: Revised and Adapted to the Course of Mathematical Instruction in the United StatesA.S. Barnes & Company, 1854 - 432 sider |
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Resultat 1-5 av 32
Side 16
... hypothenuse , and the other two sides , the base and perpen- dicular . 6. An obtuse - angled triangle is one which has an obtuse angle . 24. There are three kinds of QUADRILATERALS : 1. The trapezium , which has no two of its sides ...
... hypothenuse , and the other two sides , the base and perpen- dicular . 6. An obtuse - angled triangle is one which has an obtuse angle . 24. There are three kinds of QUADRILATERALS : 1. The trapezium , which has no two of its sides ...
Side 34
... hypothenuse and a side of the one equal to the hypothenuse and a side of the other , each to each , the triangles are equal . Let BAC and EDF be two right - angled triangles , hav- ing the hypothenuse AC = DF , and the side BA = ED ...
... hypothenuse and a side of the one equal to the hypothenuse and a side of the other , each to each , the triangles are equal . Let BAC and EDF be two right - angled triangles , hav- ing the hypothenuse AC = DF , and the side BA = ED ...
Side 64
... hypothenuses CA , CD , are equal ( D. 2 ) ; AF , the half of equal to the side DG , the half of DE : hence , the triangles are equal , and CF is equal to CG ( B. I. , P. 17 ) ; consequently , the two equal chords AB , DE , are equally ...
... hypothenuses CA , CD , are equal ( D. 2 ) ; AF , the half of equal to the side DG , the half of DE : hence , the triangles are equal , and CF is equal to CG ( B. I. , P. 17 ) ; consequently , the two equal chords AB , DE , are equally ...
Side 67
... hypothenuses CB and CA are equal ( B. I. , P. 5 ) : hence , the circumference described about the centre C , with the radius CA , will pass through B. In the same manner it may be shown , that the circumfer- ence described about the ...
... hypothenuses CB and CA are equal ( B. I. , P. 5 ) : hence , the circumference described about the centre C , with the radius CA , will pass through B. In the same manner it may be shown , that the circumfer- ence described about the ...
Side 83
... hypothenuse CA common , and the side CB = CD ; hence , there will be two equal tangents , AB , AD . The angles CAD , CAB , are also equal ( B. 1. , P. 17 ) . Scholium 2. As there can be but one line bisecting the angle BAD , it follows ...
... hypothenuse CA common , and the side CB = CD ; hence , there will be two equal tangents , AB , AD . The angles CAD , CAB , are also equal ( B. 1. , P. 17 ) . Scholium 2. As there can be but one line bisecting the angle BAD , it follows ...
Andre utgaver - Vis alle
Elements of Geometry and Trigonometry from the Works of A.M. Legendre ... Adrien Marie Legendre,Charles Davies Uten tilgangsbegrensning - 1890 |
Elements of Geometry and Trigonometry from the Works of A.M. Legendre ... Charles Davies Uten tilgangsbegrensning - 1874 |
Elements of Geometry and Trigonometry from the Works of A.M. Legendre ... Adrien Marie Legendre,Charles Davies Uten tilgangsbegrensning - 1864 |
Vanlige uttrykk og setninger
adjacent angles altitude angle ACB angle BAD base ABCD bisect centre chord circ circumference circumscribed common comp cone consequently convex surface cosine Cotang cylinder diagonal diameter distance divided draw drawn edges equations equivalent feet figure find the area frustum given angle given line given point gles greater hence homologous homologous sides hypothenuse included angle inscribed circle intersect less Let ABC let fall logarithm magnitudes measured by half middle point number of sides oblique lines opposite parallelogram parallelopipedon pendicular perimeter perpendicular plane MN polyedral angle polyedron PROBLEM PROPOSITION pyramid quadrant radii radius ratio rectangle regular polygon right angles right-angled triangle Scholium secant segment side BC similar sine slant height solidity sphere spherical polygon spherical triangle square described straight line Tang tangent THEOREM triangle ABC triangular prism triedral angles vertex vertices
Populære avsnitt
Side 27 - If two triangles have two sides of the one equal to two sides of the...
Side 227 - A spherical triangle is a portion of the surface of a sphere, bounded by three arcs of great circles.
Side 256 - The logarithm of . the quotient of two numbers, is equal to the logarithm of the dividend diminished by the logarithm of the divisor.
Side 97 - The square described on the hypothenuse of a right-angled triangle is equivalent to the sum of the squares described on the other two sides.
Side 26 - The sum of any two sides of a triangle is greater than the third side.
Side 271 - The circumference of every circle is supposed to be divided into 360 equal parts, called degrees...
Side 93 - The area of a parallelogram is equal to the product of its base and altitude.
Side 358 - CUBIC MEASURE 1728 cubic inches = 1 cubic foot 27 cubic feet = 1 cubic yard...
Side 323 - A'B'C', and applying the law of cosines, we have cos a' = cos b' cos c' + sin b' sin c' cos A'. Remembering the relations a' = 180° -A, b' = 180° - B, etc. (this expression becomes cos A = — cos B cos C + sin B sin C cos a.
Side 64 - Two equal chords are equally distant from the centre ; and of two unequal chords, the less is at the greater distance from the centre.