Elementary Geometry, Plane and Solid: For Use in High Schools and AcademiesMacmillan, 1901 - 440 sider |
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Resultat 1-5 av 45
Side 14
... radii . If a straight line intersects a circle , it must cut it at two points if extended far enough , and when one circle lies partly within and partly without another , they must intersect at two points . ON THE USE OF INSTRUMENTS 26 ...
... radii . If a straight line intersects a circle , it must cut it at two points if extended far enough , and when one circle lies partly within and partly without another , they must intersect at two points . ON THE USE OF INSTRUMENTS 26 ...
Side 18
... radii are called concentric circles . 5. Describe two circles so situated that a radius of one is a diameter of the other . 6. Describe two circles so that the same line - segment is a radius of each , but so situated that the circles ...
... radii are called concentric circles . 5. Describe two circles so situated that a radius of one is a diameter of the other . 6. Describe two circles so that the same line - segment is a radius of each , but so situated that the circles ...
Side 20
... radii . Ex . 4 , p . 18 . ( 16 ) Postulate a fundamental geometrical property , or construction , which is assumed . § 27 . - ( 17 ) Axiom a statement the truth of which is admitted as soon as its meaning is understood . § 28 . ( 18 ) ...
... radii . Ex . 4 , p . 18 . ( 16 ) Postulate a fundamental geometrical property , or construction , which is assumed . § 27 . - ( 17 ) Axiom a statement the truth of which is admitted as soon as its meaning is understood . § 28 . ( 18 ) ...
Side 23
... equi- lateral . Proof . Because A is the centre of the first circle , and the line - segments AB and AC are radii , therefore AC equals AB . Because B is the centre of the other circle , 32-34 ] 23 TRIANGLES AND PARALLELOGRAMS.
... equi- lateral . Proof . Because A is the centre of the first circle , and the line - segments AB and AC are radii , therefore AC equals AB . Because B is the centre of the other circle , 32-34 ] 23 TRIANGLES AND PARALLELOGRAMS.
Side 24
... radii , therefore BC equals BA . That is , AC and BC are each equal to AB . Hence AC equals BC . ( Axiom 1 ) Therefore AB , AC , BC are all equal , and the triangle ABC is equilateral . EXERCISES 1. Is this proposition a problem or a ...
... radii , therefore BC equals BA . That is , AC and BC are each equal to AB . Hence AC equals BC . ( Axiom 1 ) Therefore AB , AC , BC are all equal , and the triangle ABC is equilateral . EXERCISES 1. Is this proposition a problem or a ...
Andre utgaver - Vis alle
Elementary Geometry, Plane and Solid: For Use in High Schools and Academies Thomas Franklin Holgate Uten tilgangsbegrensning - 1901 |
Elementary Geometry, Plane and Solid; for Use in High Schools and Academies Thomas F 1859-1945 Holgate Ingen forhåndsvisning tilgjengelig - 2018 |
Elementary Geometry Plane and Solid: For Use in High Schools and Academies Thomas F. Holgate Ingen forhåndsvisning tilgjengelig - 2015 |
Vanlige uttrykk og setninger
ABCD adjacent angles altitude angle BAC angle formed angles are equal apothem base bisects boundaries called centre chord circumscribed coincide construct a triangle convex convex polygon COROLLARY DEFINITION diagonals diameter dicular dihedral angle draw edges equal angles equal in area equiangular equidistant equilateral triangle EXERCISES geometrical given circle given line-segment given plane given point given straight line greater Hence hypotenuse identically equal included angle interior angles isosceles triangle length locus of points magnitudes meet mid-point number of sides opposite sides pair parallel lines parallelogram perimeter perpen plane angles point of contact point of intersection polyhedron prism produced Proof Prop PROPOSITION pyramid quadrilateral radii radius ratio rectangle reflex angle regular polygon required to prove respectively right triangle segment side BC similar sphere square straight angle subtended supplementary angle surface tangent theorem third side triangle ABC unequal vertex vertical angle volume
Populære avsnitt
Side 189 - If two triangles have one angle of the one equal to one angle of the other and the sides about these equal angles proportional, the triangles are similar.
Side 232 - The formula states that the square of the hypotenuse of a right triangle is equal to the sum of the squares of the base and altitude.
Side 57 - If two triangles have two sides of the one equal respectively to two sides of the other, but the included angle of the first greater than the included angle of the second, then the third side of the first is greater than the third side of the second. Given A ABC and A'B'C...
Side 78 - The line which joins the mid-points of two sides of a triangle is parallel to the third side and equal to one half of it.
Side 45 - Prove that, if two sides of a triangle are unequal, the angle opposite the greater side is greater than the angle opposite the less.
Side 233 - A polygon of three sides is called a triangle ; one of four sides, a quadrilateral; one of five sides, a, pentagon; one of six sides, a hexagon ; one of seven sides, a heptagon ; one of eight sides, an octagon ; one of ten sides, a decagon ; one of twelve sides, a dodecagon.
Side 29 - If two triangles have two sides, and the included angle of the one equal to two sides and the included angle of the other, each to each, the two triangles are equal in all respects.
Side 202 - The area of a triangle is equal to half the product of its base by its altitude.
Side 163 - ... they have an angle of one equal to an angle of the other and the including sides are proportional; (c) their sides are respectively proportional.
Side 231 - Two parallelograms are similar when they have an angle of the one equal to an angle of the other, and the including sides proportional.