Elements of GeometryAmerican Book Company, 1896 - 540 sider |
Inni boken
Resultat 1-5 av 31
Side vi
... LOCI 283 PROBLEMS OF CONSTRUCTION . 285 BOOK VII POLYEDRONS 287 PRISMS AND PARALLELOPIPEDS 288 PYRAMIDS 308 SIMILAR POLYEDRONS . 326 REGULAR POLYEDRONS 335 GENERAL THEOREMS ON POLYEDRONS 345 PROBLEMS OF DEMONSTRATION 348 PROBLEMS OF ...
... LOCI 283 PROBLEMS OF CONSTRUCTION . 285 BOOK VII POLYEDRONS 287 PRISMS AND PARALLELOPIPEDS 288 PYRAMIDS 308 SIMILAR POLYEDRONS . 326 REGULAR POLYEDRONS 335 GENERAL THEOREMS ON POLYEDRONS 345 PROBLEMS OF DEMONSTRATION 348 PROBLEMS OF ...
Side vii
Andrew Wheeler Phillips, Irving Fisher. MEASUREMENT OF SPHERICAL FIGURES PROBLEMS OF DEMONSTRATION LOCI PROBLEMS OF CONSTRUCTION . PROBLEMS FOR COMPUTATION BOOK IX MEASUREMENT OF THE CYLINDER , CONE , AND SPHERE . CYLINDER THE CONE THE ...
Andrew Wheeler Phillips, Irving Fisher. MEASUREMENT OF SPHERICAL FIGURES PROBLEMS OF DEMONSTRATION LOCI PROBLEMS OF CONSTRUCTION . PROBLEMS FOR COMPUTATION BOOK IX MEASUREMENT OF THE CYLINDER , CONE , AND SPHERE . CYLINDER THE CONE THE ...
Side 54
... any two perpendicular lines , AO and BC , and place the two triangles so that their right angles shall coincide with the right angles at 0 and their equal sides fall along OA . 102. Def . - A line is the locus of 54 PLANE GEOMETRY.
... any two perpendicular lines , AO and BC , and place the two triangles so that their right angles shall coincide with the right angles at 0 and their equal sides fall along OA . 102. Def . - A line is the locus of 54 PLANE GEOMETRY.
Side 55
... locus of all points which satisfy a given condition , if all points in that line satisfy the condi- tion , and no points out of that line satisfy it . Question - What is the locus of all points three inches from a given point ? Prove it ...
... locus of all points which satisfy a given condition , if all points in that line satisfy the condi- tion , and no points out of that line satisfy it . Question - What is the locus of all points three inches from a given point ? Prove it ...
Side 57
... locus of all points equally distant from two fixed points is a straight line bisecting at right angles the line joining the fixed points . ] Hence O is equally distant from B and C. Hence O lies in PP ' , the locus of points equally ...
... locus of all points equally distant from two fixed points is a straight line bisecting at right angles the line joining the fixed points . ] Hence O is equally distant from B and C. Hence O lies in PP ' , the locus of points equally ...
Innhold
2 | |
15 | |
32 | |
60 | |
66 | |
75 | |
87 | |
106 | |
154 | |
170 | |
193 | |
196 | |
202 | |
229 | |
235 | |
246 | |
257 | |
270 | |
282 | |
288 | |
308 | |
326 | |
335 | |
420 | |
430 | |
444 | |
456 | |
463 | |
469 | |
491 | |
497 | |
504 | |
511 | |
515 | |
523 | |
529 | |
538 | |
Andre utgaver - Vis alle
Vanlige uttrykk og setninger
ABCD adjacent angles allel altitude angles are equal apothem axis bisecting bisector centre chord circumference circumscribed coincide construct Def.-The Defs Defs.-A diagonals diameter diedral angles distance divided draw equally distant equilateral triangle equivalent Exercise.-The face angles figure Find the area frustum geometry given circle given line given point given straight line GIVEN TO PROVE given triangle Hence hypotenuse lateral area lateral edges lateral faces locus meet middle points number of sides parallel lines parallelogram parallelopiped perimeter perpendicular plane geometry plane MN polyedral angle polyedron prism prismatic surface pyramid Q. E. D. PROPOSITION quadrilateral radical axis radii radius ratio of similitude rectangle regular polygon right angles right triangle segment similar slant height sphere spherical polygon spherical triangle square straight line joining surface symmetrical tangent tetraedron THEOREM triangle ABC triangles are equal triangular prism triedral vertex vertices volume
Populære avsnitt
Side 30 - If two triangles have two sides and the included angle of one, equal respectively to two sides and the included angle of the other, the triangles are equal. C...
Side 466 - The area of a regular inscribed hexagon is a mean proportional between the areas of the inscribed and circumscribed equilateral triangles.
Side 315 - The frustum of a triangular pyramid is equivalent to the sum of three pyramids whose common altitude is the altitude of the frustum and whose bases are the lower base, the upper base, and a mean proportional between the two bases of the frustum.
Side 205 - The areas of two regular polygons of the same number of sides are to each other as the squares of their radii or as the squares of their apothems.
Side 36 - ... greater than the included angle of the second, then the third side of the first is greater than the third side of the second.
Side 379 - Two triangles are congruent if (a) two sides and the included angle of one are equal, respectively, to two sides and the included angle of the other...
Side 138 - ... twice the product of one of these sides and the projection of the other side upon it.
Side 57 - The straight line joining the middle points of two sides of a triangle is parallel to the third side, and equal to half of it.
Side 137 - If from a point without a circle a tangent and a secant be drawn, the tangent is a mean proportional between the whole secant and its external segment.
Side 147 - The product of two sides of a triangle is equal to the product of the diameter of the circumscribed circle and the altitude upon the third side.